If triangles AMN and ABC are similar, then
AM/AB = AN/AC
or
AM/(AM + MB) = AN/(AN + NC)
Check if this is true:
AM/AB = 21/(21 + 9) = 21/30 = 7/10
AN/AC = 14/(14 + 6) = 14/20 = 7/10
The angle at vertex A is common to both of the triangles.
Then by the side-angle-side (SAS) similarity theorem, the triangles are indeed similar.
Answer:
B is your answer
Step-by-step explanation:
Answer: x=3
Step-by-step explanation: Subtract 6 from both sides, Simplify
15−6 to 9, and then divide both sides by three.
3x=15−6
3x=9
x=9/3
x=3
Hope this helps, have a BLESSED day! ☺️
Answer:
i think that would be (2,0)
