18w (please check for sure though, cause im not 100% )
Answer:
The point estimate for this problem is 0.48.
Step-by-step explanation:
We are given that a University wanted to find out the percentage of students who felt comfortable reporting cheating by their fellow students.
A survey of 2,800 students was conducted and the students were asked if they felt comfortable reporting cheating by their fellow students. The results were 1,344 answered "Yes" and 1,456 answered "no".
<em>Let </em>
<em> = proportion of students who felt comfortable reporting cheating by their fellow students</em>
<u></u>
<u>Now, point estimate (</u>
<u>) is calculated as;</u>
where, X = number of students who answered yes = 1,344
n = number of students surveyed = 2,800
So, Point estimate (
) =
= <u>0.48 or 48%</u>
Answer:
Below.
Step-by-step explanation:
- tan 2x = -2tanx / (1 - tan^2x)
Using the identity tan^2x = sec^2x - 1 and substituting for tan^2x:
- tan 2x = -2 tanx / (1 - (sec^2x - 1))
= 2 tanx / ( - 1(sec^2x + 2))
= 2 tan x / (sec^2 x - 2)