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jok3333 [9.3K]
3 years ago
5

Which case allows for more than one triangle with the given measures to be constructed?

Mathematics
2 answers:
sesenic [268]3 years ago
6 0
The answer is b hope I helped.

Anton [14]3 years ago
5 0
<span>three sides measuring 16 m, 10 m, and 5 m</span>
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Please help me im in a rush
Trava [24]

Answer:

\frac{x}{y}  =  \frac{10}{5}   \\  =  \frac{5}{1}

1. •°• y is 5 times x

\frac{x}{y}  =  \frac{30}{5}  \\  =  \frac{6}{1}

2. •°• y is 6 times x

\frac{x}{y}  =  \frac{56}{8}  \\  =  \frac{7}{1}

3. •°• y is 7 times x

\frac{x}{y}  =  \frac{88}{11}  \\  =  \frac{8}{1}

4. •°• y is 8 times x

2 \times \frac{7}{4}

•°• y is 2 times x

5 \times \frac{7}{4}

•°• y is 5 times x

8 \times \frac{7}{4}

•°• y is 8 times x

11 \times \frac{7}{4}

•°• y is 11 times x

3 0
2 years ago
according to the nutrition lavel, one large egg contains 6 grams of protein. This is 100% of the daily value (DV) for protein. E
ziro4ka [17]
Well fractions are set up over 100 so if it's 100% it would equal 100/100 or your answer, 1.
3 0
3 years ago
How do I do this what is it asking
padilas [110]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\\\&#10;&#10;\begin{array}{rllll} &#10;% left side templates&#10;f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}&#10;\end{array}

now.. notice the template above

so hmm  \bf \begin{array}{llll}&#10;% right side info&#10;\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\&#10;\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}&#10;\\\\&#10;\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\&#10;\end{array}

\bf \begin{array}{llll}&#10;&#10;&#10;\bullet \textit{ vertical shift by }{{  D}}\\&#10;\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{ period of }\frac{2\pi }{{{  B}}}&#10;\end{array}

on a)  D is 2
on b)  D is -2
on c) A is 2
on d) A is 1/2


3 0
3 years ago
Help me :( it's algebra and I am so confused. (explanation would be nice)
Mekhanik [1.2K]

Answer:

-3x^4-3x+15x^2

Hope it helps

The 1st option

7 0
3 years ago
Read 2 more answers
I need help because I totally forgot about it
Verizon [17]
Right triangle has one degree = 45 so it's isosceles right triangle.
let y = hypotenuse of small isosceles right triangle 

y^2 = 7^2 + 7^2
y^2 = 49 + 49
y^2 = 98

so 
x^2 = 98 + 98
x^2 = 196
x = 98

answer
x = 98




5 0
4 years ago
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