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3 years ago

Which case allows for more than one triangle with the given measures to be constructed?

Mathematics

2 answers:

sesenic [268]3 years ago

6 0

The answer is b hope I helped.

Anton [14]3 years ago

5 0

<span>three sides measuring 16 m, 10 m, and 5 m</span>

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If you deposit $25,000 now at 6.5% compounded quarterly, how much will you have in 30 years?

Mice21 [21]

Answer:

$172,984.44

Step-by-step explanation:

We can use the formula

$A = P(1 + \frac{r}{n})^{nt}$ to compute the final amount

Here P is the principal amount, the original deposit = $25,000

r is the annual interest rate = 6.5% = 0.065 in decimal

n is the number of times the compounding takes place. Here it is quarterly so it is 4 times a year

t is the number of time periods ie 30 years

A is the accrued amount ie principal + interest

Computing different components,

$nt = 4 \times 30 = 120$

$r/n = 0.065/4 = .01625$

$1 + r/n = 1.01625$

$(1 + r/n)^{nt} = 1.01625^{120}$

Therefore

$A = 25000 \times 1.0625^{120} = 172,984.44$

4 0

2 years ago

HEEELLLPPP!!!!!!!!! PLEEAASEEE!!!!!!!!

Ksivusya [100]

Answer:

Step-by-step explanation:

$17. (a^{m})^{n}=a^{m*n}\\\\a^{m}*a^{n}=a^{m+n}\\\\-3k^{2}*(4k^{5})^{3}=-3k^{2}*4^{3}*k^{5*3}\\\\ = -3k^{2}*64*k^{15}\\\\= (-3)*64*k^{2+15}\\\\= - 192k^{17}$

$19. \dfrac{a^{m}}{a^{n}}=a^{m-n}\\\\\\\dfrac{(-7p^{4})*(-8p^{5})}{2p^{3}}= \dfrac{(-7)*(-8)*p^{4}*p^{5}}{2p^{3}}\\\\\\=(-7)*(-4)*p^{4+5-3} \\\\= 28p^{6}\\$

$20)\dfrac{15a^{16}b^{11}}{(3a^{4}b^{2})^{3}}=\dfrac{15a^{16}b^{11}}{3^{3}*a^{4*3}*b^{2*3}}\\\\\\=\dfrac{15a^{16}b^{11}}{27*a^{12}*b^{6}}\\\\=\dfrac{5*a^{16-12}*b^{11-6}}{9}\\\\\\=\dfrac{5a^{4}b^{5}}{9}$

4 0

2 years ago

When Sam gave Clarissa 105 chocolates, Clarissa had 5 times as many chocolates as Sam. They had 504 chocolates altogether. How m

IgorLugansk [536]

Answer:

315 chocolate

Step-by-step explanation:

Let Sam's chocolate be S

Let Clariss's chocolate be C

When Sam gave Clarissa 105 chocolates, Clarissa had 5 times as many chocolates as Sam.

This can be written as:

C = 5S

The sum of their chocolate is 504 i.e

S + C = 504

Now, let us determine the chocolate of Clarissa after receiving 105 chocolate from Sam. This can be obtained as follow:

S + C = 504

But: C = 5S

S + 5S = 504

6S = 504

Divide both side by 6

S = 504/6

S = 84.

C = 5S = 5 x 84 = 420

Therefore, Clarissa have 420 chocolate after receiving 105 chocolate from Sam.

Now, to know the amount of chocolate that Clarissa has at first, we simply subtract 105 from the present amount that Clarissa have. This is illustrated below:

Amount of chocolate that Clarissa has a first = 420 – 105 = 315

Therefore, Clarissa had 315 chocolate at first.

3 0

3 years ago

NEED HELP ASAP!!!!!!!!!!

Alona [7]

Answer:

i dont know what your asking

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

I WILL GIVE U BRAINLYEST!! PLSS HELP!

Maslowich

Answer:

the mean number of siblings is 8

Step-by-step explanation:

all you have to do is look at the graph.

8 0

3 years ago