2x^2 - quadratic - monomial
-2 - constant - monomial
3x - 9 - linear - binomial
-3x^2 - 6x + 9 - quadratic - trinomial
For this, you use the Law of Distribution and multiply -1 by all terms in the parentheses. 7 • -1 = -7; -c • -1 = c. Then you combine them, but since c is a variable, -7 + c is the most simplified it can get. I hope this helped!
Simple :)
Area of shaded part = are of 1/4 circle - area of both triangles.
Are of circle = pie r^2 so 100x3.14 = 314 cm2.
Area of triangle AOB= area of triangleDOE = bh/2= 5x10/2= 25 each
However, the traingles share a common area which is quad DOB(I)
Lets take traingle AOE, whose are is bh/2=10x10/2=50cm2.
50-area of triangle A(I)E= 50-(
The diameter is 10 so it would be pi•radius squared 3.14•52sq or 3.14•10•2=78.54 the base of the circle is 78.54
