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4 years ago

Le 1

Mathematics

1 answer:

Olin [163]4 years ago

6 0

They would sell the candy for 2 dollars and 30 cents

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PLZZ HELP I NEED AN EXPERT ANSWER

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This one is D.

The y-intercept has to be below 20 and the slope has to be above 1.

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3 years ago

I do not understand , please help.

ivolga24 [154]

the slope is 1/2 and the whole lines equation is y=1/2x + 2

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3 years ago

Read 2 more answers

Jill makes purses and backpacks. To make each purse,she uses 1foot less than half the amount of fabric she uses to make a backpa

nikklg [1K]

Answer:

Step-by-step explanation:

Jill makes purses and backpacks.

Let x represent the number of foot of fabric required to make a purse.

Let y represent the number of foot of fabric required to make a backpack.

To make each purse,she uses 1 foot less than half the amount of fabric she uses to make a backpack. This means that

x = (y/2) - 1

Therefore, the amount of fabric that Jill needs to make backpack will be

y/2 = x-1

y = 2(x-1) = 2x - 2

The number of feet of fabric that she will use to make a purse is

x = (y/2) - 1

4 0

3 years ago

A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect

Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

D = a person has the disease

X = the test is positive.

The information provided is:

$P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99$

Compute the probability that a person does not have the disease as follows:

$P(D^{c})=1-P(D)=1-0.88=0.12$

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

$P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264$

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

$P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188$

Compute the probability that a randomly selected person is tested negative as follows:

$P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})$

$=0.0264+0.1188\\=0.1452$

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0

3 years ago

The point (4,-2) is the vertex of the graph of a quadratic function. The points (8,6) and (2,0) also fall on the graph of the fu

Elina [12.6K]

Answer:

Step-by-step explanation:

y = ax² + bx + c

~~~~~~~

(4, - 2), (8, 6), (2, 0)

a(4²) + b(4) + c = - 2

a(8²) + b(8) + c = 6

a(2²) + b(2) + c = 0

16a + 4b + c = - 2 .............. (1)

64a + 8b + c = 6 ............... (2)

4a + 2b + c = 0 ................. (3)

a = 0.5 ; b = - 4 ; c = 6

y = 0.5x² - 4x + 6

Part A: (0, 6), (6, 0)

Part B: (0,6)

Part C: (6, 0)

Part D: [ 4, ∞ )

4 0

3 years ago