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borishaifa [10]
3 years ago
8

Last questions; I NEED HELP!

Mathematics
1 answer:
Hitman42 [59]3 years ago
5 0
Given that cos Ф = 5/6 I know that one side is 5 and the hypotenuse is 6 so the other side is:
a^2 = c^2 - b^2
a^2 = 6^2 - 5^2
a^2 = 36 - 25 = 11
a = \sqrt{11}

Now I know that the sin is \frac{ \sqrt{11} }{6} since sin is defined as opposite/hypotenuse

the second one uses a form of C = pi * d we are going to add the sector part to it.
C = 6 and the central angle is 4 degrees we can set up like this:
6 =  \frac{4}{360}* \pi *d
\frac{6 * 360}{4 *  \pi } = d

d = 171.974
r = 171.94/2 =85.987
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