Hope this helps. - M
Last questions; I NEED HELP!
1 answer:
Given that cos Ф = 5/6 I know that one side is 5 and the hypotenuse is 6 so the other side is:
a^2 = c^2 - b^2
a^2 = 6^2 - 5^2
a^2 = 36 - 25 = 11
a =
Now I know that the sin is
since sin is defined as opposite/hypotenuse
the second one uses a form of C = pi * d we are going to add the sector part to it.
C = 6 and the central angle is 4 degrees we can set up like this:
d = 171.974
r = 171.94/2 =85.987
a^2 = c^2 - b^2
a^2 = 6^2 - 5^2
a^2 = 36 - 25 = 11
a =
Now I know that the sin is
the second one uses a form of C = pi * d we are going to add the sector part to it.
C = 6 and the central angle is 4 degrees we can set up like this:
d = 171.974
r = 171.94/2 =85.987
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Hope this helps. - M