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2 years ago

Last questions; I NEED HELP!

Mathematics

1 answer:

Hitman42 [59]2 years ago

5 0

Given that cos Ф = 5/6 I know that one side is 5 and the hypotenuse is 6 so the other side is:
a^2 = c^2 - b^2
a^2 = 6^2 - 5^2
a^2 = 36 - 25 = 11
a = $\sqrt{11}$

Now I know that the sin is $\frac{ \sqrt{11} }{6}$ since sin is defined as opposite/hypotenuse

the second one uses a form of C = pi * d we are going to add the sector part to it.
C = 6 and the central angle is 4 degrees we can set up like this:
$6 = \frac{4}{360}* \pi *d$
$\frac{6 * 360}{4 * \pi } = d
$
d = 171.974
r = 171.94/2 =85.987

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Mr Lok is putting a pool in his backyard. His backyard is 10 m long and 8 m wide, while the pool he wants has an area of 8m2. ho

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Answer:

hope this helps and make me brainliest

Step-by-step explanation:

. You have that:

- The homeowner want the length of the swimming pool to be 4 feet longer than its width.

- He wants to surround it with a concrete walkway 3 feet wide.

- He can only afford 300 square feet of concrete for the walkway.

2. Therefore, the tota area is:

At=L2xW2

L2 is the lenght of the walkway (L2=L1+3+3⇒L2=(W1+4+6)⇒L2=W1+10).

W2 is the width of the walkway (W1+3+3⇒W2=W1+6)

3. The area of the walkway is:

A2=At-A1

A2=300 ft²

4. Therefore, you have that the width of the swimming pool is:

A2=(W1+10)(W1+6)-(W1+4)(W1)

300=(W1²+6W1+10W1+60)-(W1²+4W1)

W1²+16W1+60-W1²-4W1-300=0

12W1-240=0

W1=240/12

W1=20 ft

5. And the length is:

L1=W1+4

L1=20+4

L1=24 ft

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1 year ago

The slope of the line passing through the points (-1,5) and (1,6) is

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The answer is B, 1/2

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What is the domain and range of : y=(1/3)^x

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3 years ago

A product is made up of components A, B, C, D, E, F, G, H, I, and J. Components A, B, C, and F have a 1/10,000 chance of failure

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Answer:

The overall reliability is 99.7402 %

Step-by-step explanation:

The overall reliability of the product is calculated as the product of the working probability of the components.

For components A,B,C and F we have :

$P(failure)=\frac{1}{10000}$

⇒

$P(Work)=1-\frac{1}{10000}=\frac{9999}{10000}=0.9999$

For components D,E,G and H we have :

$P(failure)=\frac{3}{10000}$

⇒

$P(Work)=1-\frac{3}{10000}=\frac{9997}{10000}=0.9997$

Finally, for components I and J :

$P(failure)=\frac{5}{10000}$

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$P(Work)=1-\frac{5}{10000}=\frac{9995}{10000}=0.9995$

Now we multiply all the working probabilities. We mustn't forget that we have got ten components in this case :

Components A,B,C and F with a working probability of 0.9999

Components D,E,G and H with a working probability of 0.9997

Components I and J with a working probability of 0.9995

Overall reliability = $(0.9999)^{4}(0.9997)^{4}(0.9995)^{2}=0.997402$

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Answer:

Step-by-step explanation:

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For example, the probability that it would rain on Friday is between o and 1. If it rains, a value of one is attached to the event. If it doesn't a value of zero is attached to the event.

the probability it would snow is 0.07 or 7%. this is quite low. so, it is unlikely that it would snow

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