Answer:
The correct answer is :
1. Line PQ (One line PQ).
Step-by-step explanation:
The first step to solve this question is to draw the plane A with the points P and Q lying on it.
We know that given two different points there is only one line that contains this two different points.
Let's analyze each option.
''2. Lines PQ and QP''
This option is wrong because there aren't two different lines. In fact it is only one line that can be named line PQ or line QP.
''3. The 2 lines PQ and QP plus another line that does not lie in plane A.''
This option is assuming that exist three lines that contain P and Q. This option is also wrong.
''1. Line PQ''
This option is correct. It will be clarify with the drawing I will attach.
''We can't name them all!''
This option is assuming that exist infinite lines that contain P and Q. This option is wrong.
In the drawing I call the line that contains P and Q as line L.
Given that P and Q lie in plane A necessarily the line L must lie on the plane A.
9514 1404 393
Answer:
- Tyler
- 2 hundredths of a mile
Step-by-step explanation:
The graph is a little difficult to read, but we note that there are 6 grid lines between times that are 2 minutes apart. So, each grid line stands for 2/6 = 1/3 minute.
At the 1-mile mark, the graph crosses 1 grid line above 8 minutes, indicating it takes Tyler 8 1/3 minutes to run 1 mile.
Then in 10 minutes, Tyler will run ...
distance = speed · time = 1 mile/(8 1/3 min) · 10 min
= 1/(25/3)·10 = 10·3/25 = 30/25 = 1.2 . . . . miles
__
The equation tells you that Elena runs each mile in 8.5 minutes. To see how far she runs in 10 minutes, we can solve ...
10 = 8.5x
x = 10/8.5 ≈ 1.18 . . . . miles
So, Tyler runs farther in 10 minutes by a distance of ...
1.20 -1.18 = 0.02 . . . . miles
Answer:
375 + 320
Step-by-step explanation:
375 adult
320 students
equals 395
Answer:
and 
Step-by-step explanation:
Given
See attachment for complete question
Required
Determine the equilibrium solutions
We have:


To solve this, we first equate
and
to 0.
So, we have:


Factor out R in 

Split
or 
or 
Factor out W in 

Split
or 
Solve for R


Make R the subject


When
, we have:




Collect like terms

Solve for W




When
, we have:



Collect like terms

Solve for R


So, we have:

When
, we have:





So, we have:

Hence, the points of equilibrium are:
and 