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xenn [34]
3 years ago
12

Drag each angle measure to the correct location. Each angle measure can be used more than once.

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
8 0

Answer:

4 >  {47 + 1 = fs \cos( \cos(34 +  \sqrt[33]{?} ) )  \times \frac{?}{?} }^{?}

ok I hope it's good answer

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What is the area of this shape?
m_a_m_a [10]

Step-by-step explanation:

idk the answer but find the area of a circle with the radius of 45 m and then find the area of the rectangle then add them together.

5 0
3 years ago
A marble is randomly selected from a bag containing 15 black, 12 white, and 6 clear marbles. Find P(not clear). Round to the nea
dexar [7]
15+12+6= total number of marbles
33= total
Not clear marbles = 15+12 or 27
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3 years ago
Suppose we roll a fair six-sided die 20 times and draw ten cards from a standard 52-card deck. Let X be the number of "6"s rolle
Lera25 [3.4K]

Answer:

a) Expected value = 6.406

Variance = 4.905

Standard deviation = 2.45

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Step-by-step explanation:

a) Let's suppose that:

X₁ = number of 6´s

X₂ = number of Jack, Queen, King or Aces

The mean of X₁ is:

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The variance of X₁ is:

Var-X_{1} =np(1-p)=3.33(1-(1/6))=2.775

The mean of X₂ is:

MeanX₂ = 10 * (16/52) = 3.076

The variance of X₂ is:

Var-X_{2} =3.076(1-(16/52))=2.13

The expect value of X is:

Xexp = MeanX₁ + MeanX₂ = 3.33 + 3.076 = 6.406

The variance of X is:

VarX = VarX₁ + VarX₂ = 2.775 + 2.13 = 4.905

The standard deviation is:

Xdevi = 4.905/2 = 2.45

b) The probability of drawing at least five six out of 20 rolls is equal to:

∑(1/6)ˣ(5/6)²⁰⁻ˣ = 0.231 with x = 5

The probability of at least 4 Jack, Queen, Kings or Aces is:

∑(16/52)ˣ(1-(16/52))¹⁰⁻ˣ = 0.37 with x = 4

The probability of given event is equal to:

P = 0.231 * 0.37 = 0.08547

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3 years ago
How do you do applications of systems
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The application system is like a test!
Example: To apply for take a walk-in exam held at the DCAS Computer Based testing and applications.
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Dany bought a total of 20 game cards some
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12 cards : $0.25
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