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xenn [34]
3 years ago
12

Drag each angle measure to the correct location. Each angle measure can be used more than once.

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
8 0

Answer:

4 >  {47 + 1 = fs \cos( \cos(34 +  \sqrt[33]{?} ) )  \times \frac{?}{?} }^{?}

ok I hope it's good answer

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Gold in the form of solid cylinders will be molded into solid blocks. Each cylinder has a diameter of 6.19 cm and a height of 6
Taya2010 [7]
First, solve for the volume (V) of each cylinder by the equation,
                                     V = πd²h / 4
where d and h are diameter and height, respectively. Substituting the given values,
                                     V = π(6.19 cm)² x (6 cm) / 4 = 180.56 cm³
To determine the number of cylinders needed, divide the volume of the solid block by the volume of the cylinder,
                                       n = 360 cm³ / 180.56 cm³ = 1.99
Thus, approximately 2 cylinders are needed to mold one block of gold. 
5 0
3 years ago
Read 2 more answers
Y=2x+5 and y=3x+2 using substitution strategy
WINSTONCH [101]

Answer:

Hi there the answer will be (3,11)

Since you are using the substitution way, you first plug in one of the y's into the other equation and you can see that they are set equal to each other.

2x+5=3x+2

Then you subtract 2x on both sides to get the x's on the same side

and you get 5=x+2

Then you subtract 2 on both sides, and you get x to equal to 3

then you plug x into any equation to get y to equal 11

y= 2(3)+5

5 0
3 years ago
a total of $21,000 is invested in two bonds that pay 4% and 7.5% simple interest. The bond with 7.5 % interest rate earned 6 tim
hjlf
21000=a+b
ax.075xt=6xbx.04xt
t cancels out
a=3.2b
21000= 3.2b+b
21000=4.2b
b=5000
a=16000

account with 7.5% had 16000 invested in it.
account with 4% had 5000 invested in it
4 0
3 years ago
Write a polynomial f(x) that satisfies the given conditions. Polynomial of lowest degree with zeros of -2 (multiplicity 3), 3 (m
Genrish500 [490]

Answer:

Step-by-step explanation:

Polynomial f(x) has the following conditions: zeros of -2 (multiplicity 3), 3 (multiplicity 1), and with f(0) = 120.

The first part zeros of -2 means (x+2) and multiplicity 3 means (x+2)^3.

The second part zeros of 3 means (x-3) and multiplicity 1 means (x-3).

The third part f(0) = 120 means substituting x=0 into (x+2)^3*(x-3)*k =120

(0+2)^3*(0-3)*k = 120

-24k = 120

k = -5

Combining all three conditions, f(x)

= -5(x+2)^3*(x-3)

= -5(x^3 + 3*2*x^2 + 3*2*2*x + 2^3)(x-3)

= -5(x^4 + 6x^3 + 12x^2 + 8x - 3x^3 - 18x^2 - 36x - 24)

= -5(x^4 + 3x^3 - 6x^2 - 28x -24)

= -5x^4 - 15x^3 + 30x^2 + 140x + 120

6 0
3 years ago
Read 2 more answers
PLEASE HELPPP!!!?!?? I REALLY NEED IT!!!
DIA [1.3K]

All of the above is the correct answer

4 0
3 years ago
Read 2 more answers
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