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SCORPION-xisa [38]
3 years ago
10

True or False

Mathematics
2 answers:
attashe74 [19]3 years ago
7 0
When we say right triangle, it is a triangle that has at least one angle equal to 90 degrees. In addition, an isosceles triangle can also be considered a right triangle given that it has two sides that are equal. In the given measurements above, the set is not considered as measurements of a right triangle. Therefore, the answer is FALSE. Hope this answer helps.

liubo4ka [24]3 years ago
4 0
False the triangle is not a right triangle because the legs don't make a right angle


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PLEASE HELP I NEED TO PASS THIS CLASSS!!!!!!!!!!
Nuetrik [128]

Answer:

1, 2, 4

Step-by-step explanation:

The triangles are similar by AAA or SSS (yes)

The sides are proportional (yes)

The length of AB is 21, not 15 (no)

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The dilation is an enlargement, not reduction (no)

5 0
4 years ago
a 23 gram sample of a substance thats a by-product of fireworks has a K-value of .13. whats the substances half life in days
nata0808 [166]
Given:
Initial mass, m₀ = 23 g
Decay constant, k = 0.13

Exponential decay obeys the equation
m(t)=m_{0} e^{-kt}
where t = time, days

For half life, the mass is m = m₀/2.
Therefore
e^{-0.13t} = \frac{1}{2} \\ -0.13t = ln(0.5)\\t= \frac{ln(0.5)}{-0.13} =5.33

Answer: The half life is 5.33 days
3 0
3 years ago
Read 2 more answers
Find dy, dx if f(x) = (x + 8)3x. 3xln(x + 8) the product of the quantity 3 times the natural log of the quantity x plus 8 plus 3
boyakko [2]
F(x) = 9x^2(x + 8)^2
8 0
3 years ago
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What is the area of the triangle in the diagram?
Vladimir [108]

1/2sqrt((x_1^2+y_1^2)(x_2^2+y_2^2))

The area of a triangle is equal to 1/2bh (one half base times height). Since this is a right triangle, the base and height are the two legs connected to the 90* angle. To find the values of these sides, we will use Pythagorean Theorem, root a squared plus b squared.

Short leg: <x(1),y(1)>

This leg can be seen as the hypotenuse of an invisible right triangle. The x value, x(1), is how far over the x value has gone from the origon at x=0. Imagine a leg alone the x-axis, going from (0,0) to (x(1),0). The y value of the point, y(1), works the same way. This leg will go from our previous mark at (x(1),0) to the point (x(1),y(1)). This shows that the short leg of the main triangle is the hypotenuse, with a height of y(1) and base of x(1). Pythagoreum Theorem shows that the length of this leg is equal to sqrt(x_1^2+y_1^2).

Long leg: <x(2), y(2)>

The same process works here, giving us sqrt(x_2^2+y_2^2).

Now for the area, we have the b and h values. Our equation reads 1/2sqrt(x_1^2+y_1^2)sqrt(x_2^2+y_2^2).

But we can simplify this (yay). The two square roots can be written together as sqrt((x_1^2+y_1^2)(x_2^2+y_2^2))

So the correct answer is 1/2sqrt((x_1^2+y_1^2)(x_2^2+y_2^2))

5 0
3 years ago
Read 2 more answers
How many thirds are equivalent to 4/6
fenix001 [56]
2

Divide both the top and bottom by 2 and you get 2/3
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