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3 years ago

The transitive property holds true for similar figures. Always Sometimes Never

Mathematics

2 answers:

Helga [31]3 years ago

7 0

I believe its always

liubo4ka [24]3 years ago

5 0

Answer: Always.

Step-by-step explanation:

The transitive property holds true for similar figures always because similar figures have similar shapes, the same angles and dimensions are proportional.

For example:- If figure 1 is similar to figure 2 then both have same shape and same angles and dimensions are proportional .

If figure 2 is similar to figure 3 then both have same shape and same angles and dimensions are proportional .

⇒ figure 1 is similar to figure 3 the both have same shape and same angles and dimensions are proportional as the figure 2 .

Thus the transitive property holds true for similar figures always.

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Luke bought 256 ounces of strawberries. he divided them evenly between 8 different pies.

pychu [463]

Answer:

2 pounds.

Step-by-step explanation:

We have been given that Luke bought 256 ounces of strawberries. He divided them evenly between 8 different pies. We are asked to find the pounds of strawberries that Luke put on each pie.

First of all, we will convert 256 ounces into pounds.

We know that 1 pound equals 16 ounces. To convert 256 ounces into pounds, we need to divide 256 by 16.

$256$ $ounces=\frac{256}{16}$ $pounds=16$ $pounds$

Now we will divide 16 pounds by 8 to find number of strawberries put on each pie.

$Pounds$ $of$ $strawberries$ $on$ $each$ $pie=\frac{16}{8}$

$Pounds$ $of$ $strawberries$ $on$ $each$ $pie=2$

Therefore, Luke put 2 pounds strawberries on each pie.

3 0

2 years ago

Billy takes 2 hours to paint 500 pictures. Sandy takes 3 hours to paint 450 pictures. if they work together, how long would it t

SVETLANKA909090 [29]

Billy can do 4 hours which is 1000 pictures
and Sandy 3 1/15 hours 500 pictures and 1/15 is 50.
Let me know if I'm wrong
Hope this helps

7 0

3 years ago

Urgent question in Mathematics. Solve this to get 15 points

Mnenie [13.5K]

Answer:

Step-by-step explanation:

Note that 2^4 - 2^3 = 16 - 8 = 8 = 2^3

In a similar way 2^6 - 2^5 = 64 - 32 = 32 = 2^5.

So 2^99 - 2^98 = 2^98 , 2^98 - 2^97 = 2^97 , 2^97 - 2^96 = 2^96 and so on.

Therefore when we come to the last 2 terms we have 2^1 - 2^0 = 2 - 1

= 1 , so the answer is 1.

3 0

3 years ago

Read 2 more answers

Find the area between the graph of the function and the x-axis over the given interval, if possible.

vodomira [7]

Answer:

$A= -\frac{5}{-1} - \lim_{x\to\infty} \frac{5}{x-2} = 5-0 = 5$

So then the integral converges and the area below the curve and the x axis would be 5.

Step-by-step explanation:

In order to calculate the area between the function and the x axis we need to solve the following integral:

$A = \int_{-\infty}^1 \frac{5}{(x-2)^2}$

For this case we can use the following substitution $u = x-2$ and we have $dx = du$

$A = \int_{a}^b \frac{5}{u^2} du = 5\int_{a}^b u^{-2}du$

And if we solve the integral we got:

$A= -\frac{5}{u} \Big|_a^b$

And we can rewrite the expression again in terms of x and we got:

$A = -\frac{5}{x-2} \Big|_{-\infty}^1$

And we can solve this using the fundamental theorem of calculus like this:

$A= -\frac{5}{-1} - \lim_{x\to\infty} \frac{5}{x-2} = 5-0 = 5$

So then the integral converges and the area below the curve and the x axis would be 5.

7 0

3 years ago

Can someone double check my work for this problem? I got 38°??

scoundrel [369]

We need to use Law of sine.

sin A/a = sin C/c
sin A/|CB| = sin C/|AB|

sin A/14 = sin(118⁰)/ 20
sin A = (14*sin(118⁰))/ 20

A=arcsin((14*sin(118⁰))/ 20) ≈ 38⁰

4 0

2 years ago