Answer:
The correct answer is 15 cm.
Step-by-step explanation:
Let the width of the required poster be a cm.
We need to have a 6 cm margin at the top and a 4 cm margin at the bottom. Thus total margin combining top and bottom is 10 cm.
Similarly total margin combining both the sides is (4+4=) 8 cm.
So the required printing area of the poster is given by {( a-10 ) × ( a - 8) } 
This area is equal to 125 as per as the given problem.
∴ (a - 10) × (a - 8) = 125
⇒ 
- 18 a +80 -125 =0
⇒ - 18 a -45 = 0
⇒ (a-15) (a-3) = 0
By law of trichotomy the possible values of a are 15 and 3.
But a=3 is absurd as a 
4.
Thus the required answer is 15 cm.
Answer:
1) 78.54
2) 490.87
3) diameter: 15.9999 so 16.00? circumference: 50.27
Step-by-step explanation:
The common minimum of those three numbers is 120.
Well to find this answer, I assume that you want me to help with finding the area. Let's start with the area of the stage. Off of the info you gave me, I assume that the stage and pit are rectangles. So to find the area of the rectangles, we need to use the area formula A=l×w. Plug in the numbers into the formula and we get A=10×5. So the area of the stage is 50 yards. Now do the same thing for the pit, and we get A=4×2. So the pit's area is 8 yards. Add 50 and 8 to get the total area and we get 58. So the stage and the orchestra pit take up 58 yards of floor space. Hope I helped!
First, illustrate the problem by drawing a square inside a circle as shown in the first picture. Connect each corner of the square to the center of the circle. Since the square is inscribed in the circle, they have the same center points. Each segment drawn to the corners is a radius of the circle measuring 1 unit. Also, a square has equal sides. So, the angle made between those segments are equal. You can determine each angle by dividing the whole revolution into 4. Thus, each point is 360°/4 = 90°.
Next, cut a portion of one triangle from the circle as shown in the second picture. Since one of the angles is 90°, this is a right triangle with s as the hypotenuse. Applying the pythagorean theorem,
s = √(1²+1²) = √2
So each side of the square is √2 units. The area of the square is, therefore,
A = s² = (√2)² = 2
The area of the square is 2 square units.
