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3 years ago

Find the quotient -60, 10

2 answers:

vladimir1956 [14]3 years ago

8 0

<h2>Hey there! Your answer is right here!</h2><h3>Answer: -6</h3><h3>Step-by-step explanation: </h3><h3>Take it as 60 ÷ 10.</h3><h3>You get 6.</h3><h3></h3><h3>When you divide a negative by a positive, you get a negative number.</h3><h3></h3><h3>Hope this helps!</h3><h3></h3>

Bond [772]3 years ago

6 0

Answer:

-6

When dividing a negative number by a positive number, your answer will result in a negative number.

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Rhe sum of three consecutive ofd numbers is 87. What is the smallest of these numbers?

neonofarm [45]

Answer:

The smallest of the said odd numbers is 27

Step-by-step explanation:

Since it is 3 odd numbers that sums up to 87, the first thing to do is to divide 87 by 3

That is 87/3 = 29, which is an odd number

The nearest odd numbers to 29 are 27 and 31, and the total of all these three odd numbers is 87

That is 27+29+31 = 87, which are consecutive odd numbers.

The smallest odd number here is therefore 27

3 0

2 years ago

The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

3 years ago

Please awnser asap<br> Factor out the trinomial 10x^2+3x-1?

g100num [7]

Answer- (5x-1)(2x+1)

let me know if you need to see work

8 0

3 years ago

How long does it takes the earth to complete one full revolution?<br><br>A. 90<br>B. 180<br>C. 365

EleoNora [17]

C.365 because one revolution takes 365.25 days or one year

7 0

3 years ago

I will give brainliest to the fastest helpful answer! :) A figure is located at (0, 0), (−3, −4), and (−3, 0) on a coordinate pl

yulyashka [42]

The 3-D shape would be created if the figure was rotated around the x-axis is a cone

<h3>What are 3-D shapes?</h3>

3-D shapes (short form of 3-Dimensional shapes) are shapes that have width, length and height

<h3>How to determine the 3-D shape?</h3>

The coordinates are given as:

(0, 0), (-3, -4) and (-3, 0)

When the above coordinates are plotted on a coordinate plane and the points are connected;

We can see that the points form a right-triangle

See attachment for the shape

As a general rule

Rotating a right-triangle across the x-axis would form a cone

Hence, the 3-D shape would be created if the figure was rotated around the x-axis is a cone

Find the quotient -60, 10​

Find the quotient -60, 10