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3 years ago

A line goes through the points (8,9) (-2,4)

Mathematics

1 answer:

SIZIF [17.4K]3 years ago

8 0

Answer:

y-9=1/2(x-8)

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(4-9)/(-2-8)

m=-5/-10

m=1/2

y-y1=m(x-x1)

y-9=1/2(x-8)

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Susan wants to mail her nephew a christmas gift. She has picked out a hat that is 27 inches long. The only box available is 15-b

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Answer:No, the hat will not fit into the box.

Step-by-step explanation:

The length of the hat is 27 inches long. The only box available is 15-by-20-by-15 inches. This represents the height , width and length of the box

Since all sides of the box are lesser than 27 inches, then the hat will not fit into the box.

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2 years ago

The graph represents the profit on the sale of boxes of cookies. what does the slope represent?

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3 years ago

(2x+1)(2x-1) find the product

VladimirAG [237]

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a^2-b^2=(a-b)(a+b)
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3 years ago

Write the equation of a circle centered at the

Fudgin [204]

Answer:

$(x+4)^2+(y+6)^2=100$

Step-by-step explanation:

Given a circle centred at the point P(-4,-6) and passing through the point

R(2,2).

To find its equation, we follow these steps.

Step 1: Determine its radius, r using the distance formula

For point P(-4,-6) and R(2,2)

$\text{Distance Formula=}\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\\text{Radius=}\sqrt{(2-(-4))^2+(2-(-6))^2} \\=\sqrt{(2+4))^2+(2+6)^2}\\=\sqrt{6^2+8^2}\\=\sqrt{100}\\Radius=10$

Step 2: Determine the equation

The general form of the equation of a circle passing through point (h,k) with a radius of r is given as: $(x-h)^2+(y-k)^2=r^2$

Centre,(h,k)=P(-4,-6)

r=10

Therefore, the equation of the circle is:

$(x-(-4))^2+(y-(-6))^2=10^2\\\\(x+4)^2+(y+6)^2=100$

3 0

3 years ago