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3 years ago

How do I do this please help!

Mathematics

1 answer:

jeka943 years ago

6 0

Answer:

put the 4x on the top and the negative 3 on the left not the bottom

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Determine the equation of the line.

Tpy6a [65]

Check the picture below.

7 0

2 years ago

order the numbers 0.64, 2/3, 65%, and 7/10, from least to greatest, and explain how you got your answer, please, thank youuuu!

Andrei [34K]

The answer is 0.64,65,2/3,7/10 how I got it is because you need to turn all the numbers into decimals
7/10=.7
2/3=0.666666.....
and the others one are already in decimal form

4 0

3 years ago

Carl collects coins compulsively, but he only likes quarters ($0.25) and dimes ($0.10). Carl currently has 125 coins for a total

Bogdan [553]

Answer:

Carl has 35 dimes and 90 quarters

Step-by-step explanation:

Let the number of quarters be q and the number of dimes be d

Total number of coins is 125;

Hence;

q + d = 125 •••••••••(i)

The total value of quarters present = q * 0.25 = 0.25q

The total value of dimes present = d * 0.1 = 0.1d

Adding both gives the total

0.25q + 0.1d =26 ••••••••(ii)

So we need to solve both equations simultaneously;

From i,

q = 125 - d

Substitute this into ii

0.25(125-d) + 0.1d = 26

31.25 -0.25d + 0.1d = 26

31.25 -26 = 0.25d -0.1d

5.25 = 0.15d

d = 5.25/0.15

d = 35

Recall; q = 125 - d = 125 -35 = 90

7 0

2 years ago

Examples! Write the equation that this model represents: <br>

Margarita [4]

Answer:

where is the

Step-by-step explanation:

photo show us

6 0

3 years ago

Read 2 more answers

The mass of the particles that a river can transport is proportional to the sixth power of the speed of the river. A certain riv

kari74 [83]

The river flows at 2 miles per hour. This is the speed of the current, or the speed at which the water itself is moving.

The mass of the particles moving in river is proportional to the sixth power of 2, or $2^6 = 64$ miles per hour. So, if x is the mass of the particle, then the speed is modeled by an inverse relationship $x * 2^6 = k$ , for some constant k.

For particles that are 15 times the usual mass, the speed of the river itself must increase for the particles to travel at the same speed as before. The mass of the particles is still proportional to the sixth power of the speed of the river, but the speed of the river can no longer be 2 miles per hour. It is some speed y, which we are solving for.

So, the key here is proportional. We can set up two proportions and cross multiply.

$\dfrac{x}{2^6} = \dfrac{15x}{y^6} \\ (x)(y^6)=(2^6)(15x)$

Cancelling our x's (because we don't need to solve for them), we have

$y^6 = 15(2^6) = 15(64)=960$

To solve for y, we must take the sixth root of both sides, or raise both sides to the one-sixth power.

$\sqrt[6]{y^6} = \sqrt[6]{960}$

Using a calculator, we see that $\sqrt[6]{960} = 3.14 \ miles \ per \ hour$ .

6 0

3 years ago