Answer: is Aaaaaaa
Step-by-step explanation:
solution:
P(passed)=P(Dr. J and passed)+P(Dr. S and passed) =0.4*0.8+(1-0.4)*0.6=0.68
hence probability that she was enrolled in Dr. J's section given passed
=P(Dr. J and passed)/P(passed)=0.4x0.8/0.68=0.4706
Answer:
2
Step-by-step explanation:
27.7-14=Cost above 500 msg
13.7=C
E=number of Extra messages sent
C=0.1E
13.7/0.1=E
137=E
Total messages=T
T=500+E
T=500+137
T=637
Danielle sent 637 messages in September
A. 8^9/2= around 11585.2375; (sqrt8)^9= around 11585.2375. So choice A shows a pair of equivalent expressions.
B. (3sqrt125)^9=1,953,125; 125^9/3=1,953,125. So choice B also shows a pair of equivalent expressions.
C. 12^2/7= around 2.03394; (sqrt12)^7= around 5,985.96759. So choice C does not show a pair of equivalent expressions.
D. 4^1/5=around 1.31951; (sqrt4)^5=32. So choice D also doesn't show a pair of equivalent expressions.
Your answers are A and B.
I hope this helps ;)
