R = 2 / (1 + sin <span>θ)
Using the following relations:
R = sqrt (x^2 + y^2)
sin </span>θ = y/R
<span>
R = 2 / (1 + y/R)
R</span>(1 + y/R<span>) = 2
</span><span>R + y = 2
R = 2 - y
sqrt(x^2 + y^2) = 2 - y
Squaring both sides:
x^2 + y^2 = (2 - y)^2
x^2 + y^2 = 4 - 4y + y^2
x^2 + 4y - 4
</span>
Answer:
When you are adding or subtracting a negative fraction, you usually want to consider the numerator as negative. The method is just the same, except now you may need to add negative or positive numerators. Example 1: ... To add the fractions with unlike denominators, rename the fractions with a common denominator.
Step-by-step explanation:
<em>I GOT YOU!!!!</em>
8) 
is -0.896 radians
9) length of arc is 41.91 cm
Solution:
8)
Given that,
is in quadrant 4
To find:
From given,
Thus value of is -51.34 degrees
Convert degrees to radians
Thus is -0.896 radians
9)
From given,
radius = 15.4 cm
<em><u>The length of arc when angle in radians is:</u></em>
Thus length of arc is 41.91 cm
Hello from MrBillDoesMath!
Answer:
5 x^3 + 15 x^2 + 15 x + 5 , none of the provided choices
Discussion:
f(x) = 5 x^3
g(x) = x+ 1
=>
(f•g)(x) =
f(g(x)) =
f(x+1) =
5 * (x+1)^3 =
5 x^3 + 15 x^2 + 15 x + 5
which is none of the provided answers.
Thank you,
MrB
Answer:
d. converges, -25
Step-by-step explanation:
An infinite geometric series converges if the absolute value of the common ratio is less than 1.
Here, the common ratio is 4/5:
| 4/5 | = 4/5 < 1
So the series converges. The sum of an infinite geometric series is:
S = a₁ / (1 − r)
where a₁ is the first term and r is the common ratio.
Here, a₁ = -5 and r = 4/5:
S = -5 / (1 − 4/5)
S = -25
