Answer: a) 0.0792 b) 0.264
Step-by-step explanation:
Let Event D = Families own a dog .
Event C = families own a cat .
Given : Probability that families own a dog : P(D)=0.36
Probability that families own a dog also own a cat : P(C|D)=0.22
Probability that families own a cat : P(C)= 0.30
a) Formula to find conditional probability :
(1)
Similarly ,

Hence, the probability that a randomly selected family owns both a dog and a cat : 0.0792
b) Again, using (2)

Hence, the conditional probability that a randomly selected family owns a dog given that it owns a cat = 0.264
Answer:
The probability that the pirate misses the captain's ship but the captain hits = 0.514
Step-by-step explanation:
Let A be the event that the captain hits the pirate ship
The probability of the captain hitting the pirate ship, P(A) = 3/5
Let B be the event that the pirate hits the captain's ship
The probability of the pirate hitting the captain's ship P(B) = 1/7
The probability of the pirate missing the captain's ship, P'(B) = 1 - P(B)
P'(B) = 1 - 1/7 = 6/7
The probability that the pirate misses the captain's ship but the captain hits = P(A) * P(B) = 3/5 * 6/7
= 0.514
Answer:
The nonzero value of c will be:
Step-by-step explanation:
Given the function


as

so

switching the sides

subtract c from both sides



Using the zero factor principle


so, the solutions to the quadratic equations are:

Therefore, a nonzero value of c will be: