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Kruka [31]
3 years ago
15

How many pieces 3/7 of a foot each can I make out of 7/2 feet of rope?

Mathematics
1 answer:
zepelin [54]3 years ago
3 0
How many 6/14 of a foot can you make out of 49/14 feet of rope?

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Jesse wants to save the same amount of money each week for a trip. he needs $3,060. if the trip 36 weeks away how much money sho
Paladinen [302]
$85 weekly if you divide 3060 by 36
8 0
3 years ago
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Verify that (a+b)+c = a+ (b+c) by taking a = -8 , b = (-8/11) , c = (-8/12)
gogolik [260]

Answer:

Step-by-step explanation:

(-8+-\frac{8}{11} ) + (-\frac{8}{12}) = -\frac{96}{11} + (-\frac{2}{3}) = -\frac{288 + 22}{33}) = -\frac{310}{33}\\ (-8) + (-\frac{8}{11} + (-\frac{2}{3})) = (-8) + (-\frac{46}{33})= -\frac{310}{33}

6 0
3 years ago
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What percent is equivalent to 8/40 ? 8% 20% 25% 40%
Nikitich [7]
First you have to get the number on the right 40 to equal 100 so do 40x2=80- +40x1.5= 100

Then do the same thing to the first number 8 so 8x2=16+8x1.5=20

then you have 20/100 right so then that number over 100 is the percent that you get ^-^ 20%
7 0
3 years ago
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Pls help in this aaaaaa
ivanzaharov [21]
The question is incorrect. X is not defined UNLESS the hexagon is a regular hexagon, which means that all sides are equal (given) AND all angles are equal (not given).

Error in question aside, and  ASSUMING the hexagon is regular, you can apply the principle that
1. the sum of exterior angles of ANY polygon is 360.
2. the sum of exterior angles and interior angles at EACH vertex is 180.
3. Multiply sum from (2) above by the number of vertices and subtract 360 gives the sum of the interior angles.
4. IF the polygon is regular (all angles equal), then each interior angle equals the result from (3) divided by n, the number of vertices.

Example for a regular heptagon (7 sides, 7 verfices).
1. Sum of exterior angles = 360
2. sum of interior and exterior angles at EACH vertex=180
3. multiply 180 by 7, subtract 360
180*7-360=900
4. since heptagon is regular, each interior angle equals 900/7=128.57 deg.


8 0
3 years ago
A rectangular parking area measuring 5000 ft squared is to be enclosed on three sides using​ chain-link fencing that costs ​$5.5
kaheart [24]

Answer:

Dimensions: 75.3778 ft and 66.3325 ft

Minimum price: $1658.31

Step-by-step explanation:

Let's call the length of the parking area 'x', and the width 'y'.

Then, we can write the following equations:

-> Area of the park:

x * y = 5000

-> Price of the fences:

P = 2*x*5.5 + y*5.5 + y*7

P = 11*x + 12.5*y

From the first equation, we have that y = 5000/x

Using this value in the equation for P, we have:

P = 11*x + 12.5*5000/x = 11*x + 62500/x

To find the minimum of this function, we need to take its derivative and then make it equal to zero:

dP/dx = 11 - 62500/x^2 = 0

x^2 = 65000/11

x = 250/sqrt(11) = 75.3778 ft

This is the x value that gives the minimum cost.

Now, finding y and P, we have:

x*y = 5000

y = 5000/75.3778 = 66.3325

P = 11*x + 62500/x = $1658.31

5 0
3 years ago
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