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3 years ago

6x + 3y = 9

2 answers:

8 0

Solution 1 ▶6(x )+ 3(y) = 9

Solution 2 ▶2(x) + 3(y) = 1

Graphic organizer ▶3(y) + 6(x) = 9⬇
3(y)+ 2(x) = 1

Solution 2⬇
keep in mind the '2' becomes a negative!

▶3(y) = -2(x) + 1
▶(y) = -2(x) ÷ 3 + 1 ÷ 3

Solution 1⬇
x-intercept

6(x )+ 3(-2)(x)÷3+1÷3) = 9
▶ 4(x) = 8
▶4(?) = 8
▶x = 2

y-intercept⬇

▶(y) = -2(x)÷3+1÷3
▶(y) = (-2÷3)(2)+1÷3 = -1
▶y= -1

x-intercept: 2
y-intercept: -1

So, therefore your answer for this problem would have to be option A. x =2 , y = -1

Airida [17]3 years ago

4 0

6x + 3y = 9
2x + 3y = 1
subtracting both equation we get
4x = 8 then
x = 2 and putting the value of x in any one equation we get the value of y
that is y = -1
options A is correct

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1. 27.46% probability that A wins the series in 3 games.

2. There is a 28.84% probability A wins the series in 4 games.

3. There is a 20.18% probability A wins the series in 5 games.

4. There is a 76.48% probability A wins the series.

5. There is a 71.825% probability A wins the series if a "best-of-three" game series is played.

Step-by-step explanation:

For each game, there are these following probabilities:

A 65% probability team A wins.

A 35% probability team B wins.

The combination formula is important to solve this problem:

This is because for example, team A winning games 1,2 and 4 and team B winning game 3 is the same as team A winning games 1,3,4 and team B winning game 2. That is, the order is not important.

$C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

1. What the probability that A wins the series in 3 games?

This is team A winning all 3 games. For each game, there is a 65% probability that team A wins. So

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2. What is the probability A wins the series in 4 games?

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There is a 28.84% probability A wins the series in 4 games.

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$C_{4,2} = \frac{3!}{2!1!} = 6$

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$P = 6*(0.65)^{3}*(0.35)^{2} = 0.2018$

There is a 20.18% probability A wins the series in 5 games.

4. What is the probability A wins the series (period)?

They can win the series in 3,4 or 5 games. So this is the sum of the answers for 1,2,3.

$P = 0.2746 + 0.2884 + 0.2018 = 0.7648$

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5. What is the probability A wins the series if a "best-of-three" game series is played?

These three following outcomes are accepted:

A - A

A - B - A

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Step-by-step explanation:

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