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Andru [333]
2 years ago
11

Please solve quickly ​

Mathematics
1 answer:
HACTEHA [7]2 years ago
5 0

Area of a circle = πr^2

Area of a sector with angle x° = (x/360) πr^2

For the smaller sector,

x = 30°

r = 6 in

Required area of sector = (30/360) × π × 6^2 = 9.424 in^2

To the nearest hundreth, Area = 9.42 in^2

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Priya's cat weighs 5 1/2 pounds and her dog weighs 8 1/4 pounds.
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Answer: The cat is 2/3 times as heavy as the dog.


Step-by-step explanation:

The weight of Priya's cat =5\frac{1}{2}\ pounds

Now, 5\frac{1}{2}=\frac{11}{2}\ pounds

The weight of her dog =8\frac{1}{4}\ pounds

8\frac{1}{4}=\frac{33}{4}\ pounds

Let cat is n times heavy as dog.

Then n=\text{cat's weight}\div\text{dog's weight}

n=\frac{{11}{2}\div\frac{33}{4}\\\Rightarrow\ n=\frac{11}{2}\times\frac{4}{33}\\\Rightarrow\ n=\frac{2}{3}

Hence, The cat is 2/3 times as heavy as the dog.

5 0
3 years ago
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The formula that describes an object's motion is given by S=ut+1/2at^2 , where S is the distance traveled, u is the initial velo
RSB [31]
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