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mamaluj [8]
3 years ago
11

What is the period of the parent cosine function, y = cos(x)?

Mathematics
2 answers:
Oksanka [162]3 years ago
8 0

Answer:

The next one is a horizontal stretch

nikklg [1K]3 years ago
4 0
We have to find the period of the parent cosine function and the period of the function showed on the graph.
Period = 2π / B, where B is the coefficient of x - term.
1. For the function: y = cos x,  B = 1
Period = 2 π / 1 = 2 π = 360°.
2. For the graphed function ( from the picture ):
Period = 6 π = 1,080°
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Which ofnthe following shows the correct use of distributive property when solving 1/3(33-x)=135,2
madam [21]

Answer: OPTION C.

Step-by-step explanation:

The missing options are:

A. (33 - x) = \frac{1}{3} * 135.2\\\\B. (\frac{1}{3} *33) - \frac{1}{3} x = \frac{1}{3} * 135.2\\\\C.(\frac{1}{3}  * 33) - \frac{1}{3} x = 135.2\\\\D. (\frac{1}{3}  * 33) + \frac{1}{3} x = 135.2

In order to solve this exercise you need to remember the following:

1. The Distributive property states that:

a(b+c)=ab+ac\\\\a(b-c)=ab-ac

2. The multiplication of signs:

(+)(+)=+\\(-)(-)=+\\(-)(+)=-\\(+)(-)=-

In this case the exercise gives you the following equation:

\frac{1}{3}(33-x)=135.2

Since you need to solve for the variable "x" in order to  find its value, the first  step you must apply in the in the procedure is to eliminate the parentheses applying the Distributive property.

Then, you must multiply everyting inside the parentheses by \frac{1}{3}.

Therefore,based on the explanation, you know that the correct use of the Distributive property is:

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3 years ago
Tamara was asked to write an example of a linear functional relationship. She wrote this example:
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  • This is because the cost of baby-sitting is linearly related to the amount of hours the nany spend with the child: the more hours the nany spends with the child, the higher the cost of baby-sitting, and this relation is constant: for every extra hour the cost increases at a constant rate of $6.5.
  • If we want to represent the total cost of baby-sitting in a graph, taking the variable "y" as the total cost of baby-sitting and the variable "x" as the amount of hours the nany remains with the baby, y=5+6.5x (see the graph attached).
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  • See table attached, were you can see the increses in total cost of baby sitting (y) when the amount of hours (x) increases.

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