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3 years ago

What is the period of the parent cosine function, y = cos(x)?

Mathematics

2 answers:

Oksanka [162]3 years ago

8 0

Answer:

The next one is a horizontal stretch

nikklg [1K]3 years ago

4 0

We have to find the period of the parent cosine function and the period of the function showed on the graph.
Period = 2π / B, where B is the coefficient of x - term.
1. For the function: y = cos x, B = 1
Period = 2 π / 1 = 2 π = 360°.
2. For the graphed function ( from the picture ):
Period = 6 π = 1,080°

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Vadim26 [7]

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4 years ago

Evaluate the expression w 2 - v + 1 for w = -2 and v = -8. <br> A. 5<br> B. 13<br> C. -11<br> D. -3

11Alexandr11 [23.1K]

W² - v + 1

(-2)² - (-8) + 1

4 + 8 + 1 = 13

B.13 is your answer

(two negatives = one positive)*
(plug in -2 for w, and -8 for v)
(is that w², or do you mean 2w?)

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Ugo [173]

Answer:

$\frac{12q^{\frac{7}{3}}}{p^{3}}$

Step-by-step explanation:

Here are some rules you need to simplify this expression:

Distribute exponents: When you raise an exponent to another exponent, you multiply the exponents together. This includes exponents that are fractions. $(a^{x})^{n} = a^{xn}$

Negative exponent rule: When an exponent is negative, you can make it positive by making the base a fraction. When the number is apart of a bigger fraction, you can move it to the other side (top/bottom). $a^{-x} = \frac{1}{a^{x}}$ , and to help with this question: $\frac{a^{-x}b}{1} = \frac{b}{a^{x}}$ .

Multiplying exponents with same base: When exponential numbers have the same base, you can combine them by adding their exponents together. $(a^{x})(a^{y}) = a^{x+y}$

Dividing exponents with same base: When exponential numbers have the same base, you can combine them by subtracting the exponents. $\frac{a^{x}}{a^{y}} = a^{x-y}$

Fractional exponents as a radical: When a number has an exponent that is a fraction, the numerator can remain the exponent, and the denominator becomes the index (example, index here ∛ is 3). $a^{\frac{m}{n}} = \sqrt[n]{a^{m}} = (\sqrt[n]{a})^{m}$

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$=\frac{8^{(2/3)}p^{(-4)}q^{(2)}}{27^{(-1/3)}p^{(-1)}q^{(-1/3)}}$ Negative exponent rule

$=\frac{8^{(2/3)}q^{(2)}27^{(1/3)}p^{(1)}q^{(1/3)}}{p^{(4)}}$ Combine the like terms in the numerator with the base "q"

$=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(2)}q^{(1/3)}}{p^{(4)}}$ Rearranged for you to see the like terms

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