In a standardized IQ test, scores are normally distributed with a mean score of 100 and a standard deviation of 15. Find the pro
bability that a randomly selected person has an IQ score higher than 125.
1 answer:
Answer:
0.0475
Step-by-step explanation:
First find the z-score.
z = (x − μ) / σ
z = (125 − 100) / 15
z = 1.67
Use a calculator or chart to find the probability. Using a chart:
P(Z > 1.67) = 1 − P(Z < 1.67)
P(Z > 1.67) = 1 − 0.9525
P(Z > 1.67) = 0.0475
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