Answer:
x= -2, x= -10
Step-by-step explanation:
x^2 + 12x + 36 = 16
Began by setting this quadratic equation to 0. To do this, in this equation you must subtract.
x^2+12x+20=0
Next, we plug this into the quadratic formula, where a in this case is 1(there is nothing in front of x^2), b is equaled to 12(there is a 12 as the coeefficient of 12x), and c is equaled to 20.
The quadratic formula is as goes:
(-b+-(this means plus or minus)√b^2-4ac)/(2a)
After pluggin in and simplifying, the answer is x= -2 and x= -10
Answer:
z=16
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
−7(z−6)=−70
(−7)(z)+(−7)(−6)=−70(Distribute)
−7z+42=−70
Step 2: Subtract 42 from both sides.
−7z+42−42=−70−42
−7z=−112
Step 3: Divide both sides by -7.
−7z
/−7
=
−112
/−7
z=16
Answer:
-0.5 is not a solution
2 is a solution
Step-by-step explanation:
To check if something is a solution of the equation, you need to substitute the value in place of the variable
15 + 2y = -12 - 4y
15 + 2(-0.5) = -12 - 4(-0.5)
15 - 1 = -12 + 2
14 ≠ -10 ∴ -0.5 is not a solution
5 - 2(3x + 5) = 3 - 10x
5 - 2[3(2) + 5] = 3 - 10(2)
5 - 2(6 + 5) = 3 - 10(2)
5 - 12 - 10 = 3 - 120
-17 = -17 ∴ 2 is a solution
Answer:
the 30th term is 239
Step-by-step explanation:
The computation of the 30th term is as follows:
As we know that
a_n = a_1 + (n-1)d
where
a_1 is the first number is the sequence
n = the term
And, d = common difference
Now based on this, the 30th term is
= 152 + (30 - 1) × 3
= 152 + 29 × 3
= 152 + 87
= 239
Hence, the 30th term is 239
Answer:
(3v-7)(2v^2+5)
Step-by-step explanation:
To factor 6v^3-14v^2+15v-35 by grouping we are going to try pair to up the pair two terms and also the last two terms. Like this:
(6v^3-14v^2)+(15v-35)
Now from each we factor what we can:
2v^2(3v-7)+5(3v-7)
Now there are two terms: 2v^2(3v-7) and 5(3v-7).
These terms contain a common factor and it is (3v-7).
We are going to factor (3v-7) out like so:
2v^2(3v-7)+5(3v-7)
(3v-7)(2v^2+5)
