You are adding 2 each time.
4 terms are given to you, with 5th term being 2
20 - 5 = 15
Multiply 15 with 2
15 x 2 = 30
Add the number gotten with the last number given
30 + 2 = 32
32, or (A) is your answer
hope this helps
Answer:
1a 2a
Step-by-step explanation:
n × (−2+5 ) = −8+20
n × 3 = 12
n = 4
2 + (n+6) = −1+6
n + 8 = 5
n = -3
For this case, the first thing we must do is define variables.
We have then:
x: number of minutes
y: total cost
We write the algebraic expression that models the problem.
We have then:
Simplifying we have:
Then, by the time the cost is equal to $ 300 we have:
From here, we clear the value of x.
Answer:
an algebraic expression for the problem is:
is there a value to y? if not, this is what I got:
Y^2 + 2y + 3
The total number of packages completed was 41 and with 60 moustraps per package so 41 x 60 = 2460. Of these, 52 traps were from the previous shift and 34 were rejects so 2460-52-34 = 2374 produced + 24 in the last unsealed package = 2374 +24 = 2398.
