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Keith_Richards [23]
3 years ago
8

Given h(x)= x^2-4 what is h(6)? A.32 B.-4 C.0 D.77

Mathematics
2 answers:
Kisachek [45]3 years ago
5 0
The answer to it is a) 32
maksim [4K]3 years ago
5 0

Answer:

A.32

Step-by-step explanation:

h(x)=x^2-4

h(6)=6^2-4

h(6)=36-4

h(6)=32

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Solution:

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Taking left-hand side, we get

L.H.S.=(2x+3y)(2x-3y)

L.H.S.=(2x)^2-(3y)^2                 [\because a^2-b^2=(a-b)(a+b)]

L.H.S.=(2)^2(x)^2-(3)^2(y)^2       [\because (ab)^x=a^xb^x]

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It is not equal to right-hand side 4x^2+6y^2. In the right hand side, there must be a negative sign instead of positive sign.

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3 years ago
235+123= solve using a number line
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3 years ago
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Answer:

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