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posledela
3 years ago
8

The intensity of light bulb measured in watts per square meter (w/m^2), varies inversely as the square of the distance d from th

e light bulb. suppose is 45 w/m^2 when the distance is 5 m. find the intensity when the distance from the light bulb is 7 m away
Mathematics
1 answer:
krek1111 [17]3 years ago
6 0

Answer:

I(7)   =  22.96 W/m²

Step-by-step explanation:

Let intensity of light, be  I(d)   where d is distance. There must be a proportionality factor K such as

I(d)  = K /d²

Now for d = 5 m    I(d)  =  K* 1/d²

then  45 * 25 = K

K =  1125

To find the intensity when the distance from the light bulb is 7 m away

I(7)   =  K / 49

I(7)   =  1125/49   W/m²

I(7)   =  22.96 W/m²

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3 years ago
Find the midpoint of the line segment with the endpoints A and B.
zavuch27 [327]

Answer:

<h2>( 6 , 7 )</h2>

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

M = (  \frac{x1 + x2}{2} , \:  \frac{y1 + y2}{2} )\\

From the question we have

m = ( \frac{2 + 10}{2} \:  , \:  \frac{6 + 8}{2} ) \\  =  (\frac{12}{2}  \: , \:  \frac{14}{2} ) \:  \:  \:  \:  \:  \:  \:

We have the final answer as

<h3>( 6 , 7 )</h3>

Hope this helps you

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2 years ago
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2 years ago
Need urgent help in mathematics!! Will mark brainliest!!!!
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₇P₅ is a permutation. you can find this setting in the statistics menu of your scientific calculator (i think).

If you don't have a scientific calculator, you can use the following formula:

nPr = \frac{n!}{(n - r)!}

₇P₅  = \frac{7!}{(7 - 5)!}

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3 0
3 years ago
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In the adjoining figure , APB and AQC are equilateral triangles. Prove that PC = BQ. ( Hint : <img src="https://tex.z-dn.net/?f=
just olya [345]

Answer:

See Below.

Step-by-step explanation:

Statements:                                                           Reasons:

\displaystyle 1)\text{ } \Delta APB \text{ and } \Delta AQC \text{ are equilateral triangles}      Given

\displaystyle 2) \text{ } m \angle PAB = 60                                                     Definition of equilateral.

3)\text{ } m \angle QAC = 60                                                     Definition of equilateral.

4)\text{ } m\angle PAB = m\angle QAC                                          Substitution

5)\text{ } m\angle PAC=m\angle PAB+m\angle BAC                       Angle Addition

\displaystyle 6)\text{ } m\angle QAB=m\angle QAC+m\angle BAC                       Angle Addition

7)\text{ } m\angle QAB=m\angle PAB+m\angle BAC                       Substitution

\displaystyle 8)\text{ } m\angle PAC=m\angle QAB                                         Substitution

9)\text{ } PA=BA                                                          Definition of equilateral

10)\text{ } AC=AQ                                                        Definition of equilateral

\displaystyle 11)\text{ } \Delta PAC \cong \Delta BAQ                                            Side-Angle-Side Congruence*

\displaystyle 12)\text{ } PC=BQ                                                        CPCTC

* SAS Congruence:

PA = BA

∠PAC = ∠QAB

AC = AQ

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