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2 years ago

What is the greatest common factor of 42a5b3, 35a3b4, and 42ab4? 7ab3 6a4b 42a5b4 77a8b7

Mathematics

2 answers:

lbvjy [14]2 years ago

3 0

The <em><u>correct answer</u></em> is:

7ab³

Explanation:

The greatest common factor is the largest thing that each term is divisible by.

The coefficients of our terms are 42, 35 and 42. Using the prime factorization for each,

42 = 6*7

6 = 2*3

42 = 2*3*7

35 = 5*7

The greatest common factor is 7.

For the variables, each term has at least a¹ and at least b³. This means that ab³ is part of the GCF; this gives us a GCF of 7ab³.

gogolik [260]2 years ago

3 0

Answer:

7ab^3

Step-by-step explanation:

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IrinaK [193]

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2 years ago

10 less than three times a number is 23. Find the number

Charra [1.4K]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

The grade appeal process at a university requires that a jury be structured by selecting six individuals randomly from a pool of

romanna [79]

Answer: a) $\dfrac{3}{874}$

b) $\dfrac{30}{3059}$

c) $\dfrac{3575}{12236}$

Step-by-step explanation:

Given : Number of students : 11

Number of faculty members : 13

Total persons : $11+13=24$

Total number of ways to structure a jury of six people from a group of 24 people :-

$^{24}C_{6}=\dfrac{24!}{6!(24-6)!}=134596$

a) Number of ways of selecting a jury of all students :-

$^{11}C_{6}=\dfrac{11!}{6!(11-6)!}=462$

Then , the probability of selecting a jury of all students :-

$\dfrac{462}{134596}=\dfrac{3}{874}$

b) Number of ways of selecting a jury of all faculty :-

$^{13}C_{6}=\dfrac{13!}{6!(13-6)!}=462$

Then , the probability of selecting a jury of all students :-

$\dfrac{1716}{134596}=\dfrac{30}{3059}$

c) Number of ways of selecting a jury of two students and four faculty :-

$^{11}C_{2}\times^{13}C_{4}=\dfrac{11!}{2!(11-2)!}\times\dfrac{13!}{4!(13-4)!}=39325$

Then , the probability of selecting a jury of all students :-

$\dfrac{39325}{134596}=\dfrac{3575}{12236}$

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3 years ago

Y-1/4=-3/8 solve for y

Leona [35]

Answer:

y=-1/8

Step-by-step explanation:

Add 1/4 to -3/8

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2 years ago

What is the result of gaining 10 pound then losing 20

kiruha [24]

Answer:

-10 pounds or 10 pounds loss

Step-by-step explanation:

you subreact 10-20 and you get -10

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3 years ago