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3 years ago

What is the greatest common factor of 42a5b3, 35a3b4, and 42ab4? 7ab3 6a4b 42a5b4 77a8b7

Mathematics

2 answers:

lbvjy [14]3 years ago

3 0

The correct answer is:

7ab³

Explanation:

The greatest common factor is the largest thing that each term is divisible by.

The coefficients of our terms are 42, 35 and 42. Using the prime factorization for each,

42 = 6*7

6 = 2*3

42 = 2*3*7

35 = 5*7

The greatest common factor is 7.

For the variables, each term has at least a¹ and at least b³. This means that ab³ is part of the GCF; this gives us a GCF of 7ab³.

gogolik [260]3 years ago

3 0

Answer:

7ab^3

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago

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The number of pieces made from rod is 49

<h3>Solution:</h3>

Given that A metal rod will be cut into pieces that are each 1/56 meters long

The rod is 7/8 meters long.

To find: number of peices made from rod

The number of peices made from rod can be calculated by dividing the total length of rod by length of each piece

$\text {number of pieces made }=\frac{\text {total length of rod }}{\text { length of each piece}}$

Here total length of rod = $\frac{7}{8}$ meters

length of each piece to be made = $\frac{1}{56}$ meters

Substituting the values in above formula, we get

$\text {number of pieces made }=\frac{\frac{7}{8}}{\frac{1}{56}}=\frac{7}{8} \times \frac{56}{1}$

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