What is the greatest common factor of 42a5b3, 35a3b4, and 42ab4? 7ab3 6a4b 42a5b4 77a8b7

Mathematics

2 answers:

lbvjy [14]2 years ago

3 0

The <em><u>correct answer</u></em> is:

7ab³

Explanation:

The greatest common factor is the largest thing that each term is divisible by.

The coefficients of our terms are 42, 35 and 42. Using the prime factorization for each,

42 = 6*7

6 = 2*3

42 = 2*3*7

35 = 5*7

The greatest common factor is 7.

For the variables, each term has at least a¹ and at least b³. This means that ab³ is part of the GCF; this gives us a GCF of 7ab³.

gogolik [260]2 years ago

3 0

Answer:

7ab^3

Step-by-step explanation:

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Read 2 more answers

Question is on the picture !

Nataly [62]

Answer: 122.5

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Explanation:

First thing to do is to find the perimeter of figure B. Add up all the sides and we get: 5+9+9+12 = 14+21 = 35.

The scale factor 7:2 means that if the perimeter of figure A was 7, then the perimeter of figure B would be 2. Or it could be 14 for A and 4 for B. And so on. The idea is that the two perimeters scale up or down together. This allows us to set up the proportion below in which we can solve for x

(perimeter of A)/(perimeter of B) = 7/2

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x = 122.5

The perimeter of figure A is 122.5

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2 years ago

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Brilliant_brown [7]

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