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Svetradugi [14.3K]
3 years ago
5

What is the greatest common factor of 42a5b3, 35a3b4, and 42ab4? 7ab3   6a4b 42a5b4 77a8b7

Mathematics
2 answers:
lbvjy [14]3 years ago
3 0

The <em><u>correct answer</u></em> is:

7ab³

Explanation:

The greatest common factor is the largest thing that each term is divisible by.

The coefficients of our terms are 42, 35 and 42.  Using the prime factorization for each,

42 = 6*7

6 = 2*3

42 = 2*3*7

35 = 5*7

The greatest common factor is 7.

For the variables, each term has at least a¹ and at least b³.  This means that ab³ is part of the GCF; this gives us a GCF of 7ab³.

gogolik [260]3 years ago
3 0

Answer:

7ab^3

Step-by-step explanation:

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In a game, a participant is given three attempts to hit a ball. On each try, she either scores a hit, H, or a miss, M. The game
Sidana [21]

Answer:

chancing for wining is 54%.

Step-by-step explanation:

possible outcomes can be given as

HHH *

HHM *

HMH

MHH *

HMM

MHM

MMH

MMM

Out of those, only 3 will have the participant win the game:

HHH, HHM, MHH.

Probability (HHH) + Probability (HHM) + Probability (MHH)

since attempts are independant.

Probability (HHH) = 0.9 *0.4 *0.9 = 0.324

Probability (HHM) = 0.9 *0.4 *0.3 = 0.108

Probability (MHH) = 0.3 *0.4 *0.9 = 0.108

Add them up and get  = (0.324+ 0.108+0.108) = 0.54

hence, chancing for wining is 54%.

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3 years ago
No files!!! <br> Will give brainliest and please don’t guess
ohaa [14]

Answer:

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Step-by-step explanation:

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