Answer:
The height of a jugglers ball that has been in the air for 1.5 seconds is 6.5 feet
Step-by-step explanation:
we are given height equation as
where
h is the height in feet of a Juggler's ball after t seconds
now, we can plug t=1.5
we can solve for h
So,
The height of a jugglers ball that has been in the air for 1.5 seconds is 6.5 feet
Answer:
The solution of the given system is (x,y) = (1,4)
Step-by-step explanation:
Here, the given system of equation is:
x = -3 + y
26 x - 5 y = 6
Now, substitute x = -3 + y in the second equation , we get
26 x - 5 y = 6 ⇒ 26 (-3 + y) - 5 y = 6
or, 26(-3) + 26(y) - 5y = 6
⇒ - 78 + 26 y - 5y = 6
⇒ 21 y = 84
⇒ y = 84 / 21 = 4 or , y = 4
So x = -3 + y = -3 + 4 = 1
Hence, the solution of the given system is (x,y) = (1,4)
For this case the distance will be given by:
d ^ 2 = (12 * 1.5) ^ 2 + (8 * 1.5) ^ 2
Rewriting we have:
d ^ 2 = (18) ^ 2 + (12) ^ 2
d ^ 2 = 324 + 144
d ^ 2 = 468
d = root (468)
d = 21.63 Km
Answer:
1) She did not find the full distance each traveled in 1.5 hours.
2) She should have used 12 km for Joseph's distance and 18 km for Isabelle's distance.
