Answer:
E. -8/3
F. 8/3
Step-by-step explanation:
9x^2-64=0
Add 64 to each side
9x^2-64+64 = 0+64
9x^2 =64
Divide each side by 9
9x^2/9 = 64/9
x^2 = 64/9
Take the square root of each side
sqrt(x^2) = ±sqrt(64/9)
We know that sqrt(a/b) = sqrt(a)/sqrt(b)
x = ±sqrt(64)/sqrt(9)
x = ± 8/3
The amount of the radioactive substance is 374.6 g
<h3>How to determine the amount of
radioactive substance?</h3>
The given parameters are:
- Initial, a = 424 mg
- Rate, r = 6%
- Time, t = 2 hours
The amount of the radioactive substance is calculated as:
A(t) = a(1 - r)^t
This gives
A(t) = 424 * (1 - 6%)^t
At 2 hours, we have:
A(2) = 424 * (1 - 6%)^2
Evaluate
A(2) = 374.6
Hence, the amount of the radioactive substance is 374.6 g
Read more about exponential functions at:
brainly.com/question/2456547
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Answer:
(C) - 3x²+6
Step-by-step explanation:
(2x²+3x-4) +(8-3x) +(-5x²+2)= 2x²<em>+3x</em><u>-4 +8</u><em>-3x</em>-5x²<u>+2 </u>= - 3x²+6
<span><span>The sum of a squared and b is given by

</span>7 times the sum of a squared and b is given by
</span><span>
while 4 times the sum of a squared and b is given by
</span>

Therefore, <span>7 times the sum of a squared and b minus 4 times the sum of a squared and b is given by

</span>
Yup it has to be a greater divedend if not answer would be completly wrong