Answer:
For the temperature to be below 32 F, following inequality must be met,
![h\geq 9.333](https://tex.z-dn.net/?f=h%5Cgeq%209.333)
Step-by-step explanation:
Let "t" be the temperature at any time.
General format of a linear equation can be given as,
y= mx + c
Where,
y ⇒ dependent variable ( in this case temperature t)
m⇒ Gradient ( the rate at which the temperature drops)
x⇒ independent variable ( hours )
c⇒ intercept ( this is the starting temperature)
Now we can substitute the given values to the above format to arrive at the equation,
![t=-3h+60](https://tex.z-dn.net/?f=t%3D-3h%2B60)
We can re-arrange the equations as ,
![3h=60-t](https://tex.z-dn.net/?f=3h%3D60-t)
=![h=20-\frac{t}{3}](https://tex.z-dn.net/?f=h%3D20-%5Cfrac%7Bt%7D%7B3%7D)
We can write this as an inequality when t = 32 F
![h\geq 20-\frac{32}{3}](https://tex.z-dn.net/?f=h%5Cgeq%2020-%5Cfrac%7B32%7D%7B3%7D)
=![h\geq \frac{28}{3}](https://tex.z-dn.net/?f=h%5Cgeq%20%5Cfrac%7B28%7D%7B3%7D)
=![h\geq 9.333](https://tex.z-dn.net/?f=h%5Cgeq%209.333)