Well on a table of data, if the y coordinates increase a lot over a short x distance then it will be steep.
In an equation, you would put it into y = mx + b form and whatever your m is will be your slope. If m is large, it will be steep.
Given
Answer
The graph touches the x-axis at -6
Hence x = -6 is the zero of the graph.
Slope intercept form is y=mx+b.
Y and x stay.
M is your slope.
B is your y-intercept.
Hope that this helps!
<span>A)x-y+3 is your answer
Proof:
(5 x)/4 - 8 y - x/4 + 7 y + 3
Put each term in (5 x)/4 - 8 y - x/4 + 7 y + 3 over the common denominator 4: (5 x)/4 - 8 y - x/4 + 7 y + 3 = (5 x)/4 - (32 y)/4 - (x)/4 + (28 y)/4 + 12/4:
(5 x)/4 - (32 y)/4 - x/4 + (28 y)/4 + 12/4
(5 x)/4 - (32 y)/4 - x/4 + (28 y)/4 + 12/4 = (5 x - 32 y - x + 28 y + 12)/4:
(5 x - 32 y - x + 28 y + 12)/4
Grouping like terms, 5 x - 32 y - x + 28 y + 12 = (28 y - 32 y) + (5 x - x) + 12:
((28 y - 32 y) + (5 x - x) + 12)/4
28 y - 32 y = -4 y:
(-4 y + (5 x - x) + 12)/4
5 x - x = 4 x:
(-4 y + 4 x + 12)/4
Factor 4 out of -4 y + 4 x + 12:
(4 (-y + x + 3))/4
(4 (-y + x + 3))/4 = 4/4×(3 + x - y) = 3 + x - y:
Answer: 3 + x - y
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That would be A...they have to have a constant ratio
