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Norma-Jean [14]
3 years ago
8

What is the slope of the line that passes through the points (-4,8) and (-14.8)?

Mathematics
1 answer:
bonufazy [111]3 years ago
3 0

Answer:

your answer is 0 because it's a horizontal line

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The awnser is D
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2 years ago
Select all irrational numbers.
const2013 [10]
The answers are A and D.
The numbers that you cannot simplify without having a radical in the answer are irrational numbers. 

√(4/16) = 1/4 or -1/4, rational number
√(9/16) = 3/4 or -3/4, rational number
√(9/4) = 3/2 or -3/2, rational number

√(3/16) = √(3)/4, NOT a rational number, cannot remove radical
√(3/4) = √(3)/2, NOT a rational number, cannot remove radical 
5 0
3 years ago
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Combine like terms <br> 9p + 2x -6p ?
Tcecarenko [31]

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3p +2x

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3 years ago
In a rational function, is the horizontal shift represented by the vertical asymptote?
ziro4ka [17]
<h3>Short Answer: Yes, the horizontal shift is represented by the vertical asymptote</h3>

A bit of further explanation:

The parent function is y = 1/x which is a hyperbola that has a vertical asymptote overlapping the y axis perfectly. Its vertical asymptote is x = 0 as we cannot divide by zero. If x = 0 then 1/0 is undefined.

Shifting the function h units to the right (h is some positive number), then we end up with 1/(x-h) and we see that x = h leads to the denominator being zero. So the vertical asymptote is x = h

For example, if we shifted the parent function 2 units to the right then we have 1/x turn into 1/(x-2). The vertical asymptote goes from x = 0 to x = 2. This shows how the vertical asymptote is very closely related to the horizontal shifting.

7 0
2 years ago
Suppose that the function f is defined. , for all real numbers, as follows.
aivan3 [116]

Answer:   <em>The values of......</em>

<em>f(-5)=\frac{9}{4}\\ \\ f(-2)= -1\\ \\ f(4)=0</em>

Step-by-step explanation:

Given function is:   \left \{ {{f(x)= \frac{1}{4}x^2 -4, if x\neq -2} \atop {=-1, if x=-2}} \right.

For f(-5),  the value of x is -5, which is not equal to -2.

So,  f(-5)= \frac{1}{4}(-5)^2 -4 = \frac{1}{4}(25)-4 =\frac{25}{4}-4=\frac{25-16}{4}=\frac{9}{4}

For f(-2),  the value of x is -2.

So,  f(-2)= -1

For f(4),  the value of x is 4, which is not equal to -2.

So,  f(4)=\frac{1}{4}(4)^2 -4 =\frac{1}{4}(16)-4 =4-4=0

5 0
3 years ago
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