What is the slope of the line that passes through the points (-4,8) and (-14.8)?
1 answer:
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Considering the given linear function, the inequality graphed is:
B. .
A linear function is modeled by:
y = mx + b
In which:
- m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
- b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.
The line intersects the y-axis at 2 units, hence the y-intercept is b = 2. The function also passes through (1,4), hence the slope is:
m = (4 - 2)/(2 - 1) = 2.
Thus the equation of the line is:
y = 2x + 2.
The left-side of the line is the values above the line, hence the inequality is:
B. .
More can be learned about linear functions at brainly.com/question/24808124
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The picture in the attached figure
we know that
If a tangent segment and a secant segment are drawn to a <span>circle </span><span>from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment
</span>so
DC²=BC*CA-----> CA=DC²/BC
DC=25
BC=14
CA=25²/14-----> CA=44.64
CA=BC+BA----> BA=CA-BC----> BA=44.64-14----> BA=30.64
BA is the diameter
hence
<span>the length of diameter BA is 30.64----> round to the nearest tenth---> 30.6
</span>
the answer is
<span>the length of diameter BA is 30.6</span>
we know that
If a tangent segment and a secant segment are drawn to a <span>circle </span><span>from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment
</span>so
DC²=BC*CA-----> CA=DC²/BC
DC=25
BC=14
CA=25²/14-----> CA=44.64
CA=BC+BA----> BA=CA-BC----> BA=44.64-14----> BA=30.64
BA is the diameter
hence
<span>the length of diameter BA is 30.64----> round to the nearest tenth---> 30.6
</span>
the answer is
<span>the length of diameter BA is 30.6</span>