D18∈{1,2,3,6,9,18}
suma e 1+2+3+6+9+18= 39
D81∈{1,3,9,27,81}
suma e 1+3+9+27+81=121
2. M8∈{0,8,16,24,32.....}
M18∈{0,18,36,54,72.....}
M21∈{0,21,42,63,84....}
M35∈{0,35,70,105,140...}
M64∈ {0,64,128,192,256...}
M111∈ {0,111,222,333,444....}
3. a) A, b) A , c) A, la d) nu e complet, e) A, f) A, g) A, h) A, i) A, k) 10 | 7*10 A, l) F, m) F, n) A, o) F, p) A, q) A, r) (36*5-40) divizibil cu 10, (180-40)=140 divizibil cu 10, A, s) 36| (64+30-50), 36 | 44 F, 60.000 divizibil cu 160
In this question, the population of the bacteria will become half after 6 hours and the duration (2 days=48 hours) and the final amount of bacteria (400 bacteria), To find the number of bacteria at the start(initial number), the calculation would be:
Final number = initial number / 2^(duration/6hours)
400= initial number / 2*(48/6)
initial number = 400 * 2^8= 102,400
It should be just 12b, since they all have the same exponent, they can all be combined.
Answer:
D.y = 3.9
Step-by-step explanation:
we can express the word problem five point two over eight = y over six mathematically;
our unknown is y, so we will keep rearranging the equation by using simple principles of algebra until we get y
cross multiply;
y×8 =5.2×6
y×8 =31.2
divide through by 8
y×8÷8 =31.2÷8
y=3.9
The correct answer is D