Answer:
77.76 times
Step-by-step explanation:
The average distance of Neptune from the sun
= 4.503 × 10
⁹ k
m
.
and Mercury = 5.791 × 10
⁷ k
m
.
Hence neptune is ( 4.503 × 10
⁹) ÷ (5.791
×
10
⁷ ) times farther from the sun than mercury
i.e.(
) × 10⁹⁻⁷ times
=
0.7776 × 10
² times
=
77.76 times.
Answer: The answer should be 0.125
Step-by-step explanation:
Hi!
We are given the information found in the picture below.
Note: The directions aren't correct, but the triangle works for this problem.
The "direct path" is the hypotenuse of this triangle.
To find this, we use the Pythagorean Theorem, where
and
are 2 legs of the triangle, and
is the hypotenuse, aka the longest side of any triangle:

We know
and
and want 



Therefore,
is approximately 
If quadrilateral JKLM has given values, as well as quadrilateral ABCD, it can be concluded from the given values if JKLM is a result of a dilation of ABCD by a scale factor of 2. Dilation factor is used to scale up a given figure. If ABCD has measurements of 1, 2, 3, and 4. Then the measurements of JKLM should be 4, 8, 12, and 16.