Answer:
dh/dt ≈ 0.55 ft/min
Step-by-step explanation:
The volume is given by the formula ...
V = (1/3)πr²h
We have r = h/2, so the volume as a function of height is ...
V = (1/3)π(h/2)²h = (π/12)h³
Then the rates of change are related by ...
dV/dt = (π/4)h²·dh/dt
dh/dt = (4·dV/dt)/(πh²) = 4(35 ft³/min)/(π(9 ft)²)
dh/dt ≈ 0.55 ft/min
Answer:
e. 72 inches
Step-by-step explanation:
Well, firstly to find the lengths of the sides, we would have to find the square root of 36 (which is 6, as 6x6=36).
Now, if we enlarge the square by SF 3, the new side lengths would be 6x3=18 inches. That is only one side.
Now we know the length of one side, we can do 18x4 (because as we all know, squares have 4 sides) to find the perimeter.
18x4=72 inches. This means the answer is option e.
The second day, she sold more.
We know 7/9 is about 0.777777777778
And 0.78 < 0.85
So the second day she sold more.
Answer:
1. P(S) = 373/580
2. P(S|A) = 53/116
3. P(S|Pa) = 481/580
Step-by-step explanation:
Given
---------------------Sale ----- No Sale-----Total
Aggressive ----265 --------315 ----------580
Passive ----------481 ---------99 -----------580
Total --------------746---------414------------1160
A = aggressive approach,
Pa = passive approach,
S = sale,
N= no sale.
(a) Computing P(S)
This is calculated as the division of customers that participated in sales by total customers
Customers that participated in sales = 265 + 481 = 746
Total Customers = 1160
P(S) = 746/1160
P(S) = 373/580
b.
P(S|A) means that the probability that a sales occur given that the aggressive method was used.
To solve this, we check the cell where Sales and Aggressive intersect
The cell element = 265
Total = 580
P(S|A) = 265/580
P(S|A) = 265/580
P(S|A) = 53/116
c.
P(S|Pa) means that the probability that a sales occur given that the passive method was used.
To solve this, we check the cell where Sales and Passive intersect
The cell element = 481
Total = 580
P(S|Pa) = 481/580
13+5=18 18-7=11
That’s the answerrrrrrrrrr
