Any of the 11 man can be chosen, and combined with any of the 8 women.
Assume we select man1. The selected committee can be:
(m1,w1), (m1,w2), (m1,w3), (m1,w4), (m1,w5), (m1,w6), (m1,w7), (m1,w8),
so there are 8 committees selections with man1 in them.
we could repeat the same procedure for the remaining 10 men, and get 8 committees where each of them is a member.
so there are 11*8=88 ways of choosing 1 man and 1 woman.
Answer: 88
Answer:what balls? If you could give a number maybe i could find an answer lol
Step-by-step explanation:
Answer:
Number 1 can form a right triangle. Numbers 2 & 3 cannot.
Step-by-step explanation:
To check if the sides are a right triangle, check if the sum of the squares of the two smaller sides equals the length of the square of the longest side. In other words, do the Pythagorean Theorem.
5² + 12² = 13²
25 + 144 = 169
169 = 169
<u><em>They are equal therefore Number 1 can form a right triangle.</em></u>
5² + 7² = 9²
25 + 49 = 81
74 = 81
<em>They are not equal, therefore Number 2 can't form a right triangle.</em>
<em />
10² + 12² = 30²
100 + 144 = 900
244 = 900
<em>They are not equal, therefore Number 3 can't form a right triangle.</em>
Answer:
d.
Step-by-step explanation:
Answer:
76
Step-by-step explanation:
so first the equation for the situation has been given which is
194=1/2x + 2x - 16
now you can just solve since it's a linear equation
194=2.5x -16
take 16 to the other side to get
210=2.5x
solve to get x (adult price)
which is 84
remember the. child's price is 8 less
84-8=76
