2+3/5x-1-1/4x
2+3x-1/5-1-x/5
2+3/5x-1-x/5
1+3/5x-x/5
1+2/5x
Y=-1.5x + 8
hope this helps :) (please mark brainliest!)

_________________________________
Step(1)
To find q(a) we just need to put a instead of x in q(x) function.
Let's do it...

Multiply sides by -2 :


_________________________________
Step (2)
To find q(a+1) we just need to put a+1 instead of x in q(x) function.
Let's do it...



_________________________________
Step (3)



And we're done.
Thanks for watching buddy good luck.
♥️♥️♥️♥️♥️