Answer:
$42 - 19 = 23 - 15 = $8
Step-by-step explanation:
Answer:
Step-by-step explanation:
Suppose we think of an alphabet X to be the Event of the evidence.
Also, if Y be the Event of cheating; &
Y' be the Event of not involved in cheating
From the given information:



Thus, 
P(Y') = 1 - 0.01
P(Y') = 0.99
The probability of cheating & the evidence is present is = P(YX)



The probabilities of not involved in cheating & the evidence are present is:


(b)
The required probability that the evidence is present is:
P(YX or Y'X) = 0.006 + 0.000099
P(YX or Y'X) = 0.006099
(c)
The required probability that (S) cheat provided the evidence being present is:
Using Bayes Theorem



Answer:
Step-by-step explanation:
Let the sides of the triangle be a, b and c.
<u>We have:</u>
- P = a + b + c = 29
- a = 2b - 5
- c = b + 6
<u>Substitute values and solve for b:</u>
- 2b - 5 + b + b + 6 = 29
- 4b + 1 = 29
- 4b = 28
- b = 7
<u>Find a and c:</u>
- a = 2*7 - 5 = 14 - 5 = 9
- c = 7 + 6 = 13
<u>The sides are:</u> 7, 9, 13
Answer:
T.A = 54 + 9/2 √3
Step-by-step explanation:
∵ The figure is triangular prism
∴ T.A = perimeter of the base × height + 2 × area of the base
∵ The base is an equilateral Δ with side length 3"
∴ The perimeter of the base = 3 × 3 = 9 inches
∴ The area of the base = 1/4 S² √3 = 1/4 (3)²√3 = 9/4 √3 inches²
∵ The length of the height of the prism = 6"
∴ T.A = 9 × 6 + 2 × 9/4 √3 = 54 + 9/2 √3
∴ T.A = 54 + 9/2 √3 inches²