The possible zeros of f(x) = 3x^6 + 4x^3 -2x^2 + 4 are
The function is given as:
f(x) = 3x^6 + 4x^3 -2x^2 + 4
The leading coefficient of the function is:
p = 3
The constant term is
q = 4
Take the factors of the above terms
p = 1 and 3
q = 1, 2 and 4
The possible zeros are then calculated as:
So, we have:
Expand
Solve
Hence, the possible zeros of f(x) = 3x^6 + 4x^3 -2x^2 + 4 are
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Answer:
B
Step-by-step explanation:
We know that:
-measuring a cone
-diameter: 18 units
-height: 8 units
We need to know how to find the volume of this cone. To do this, we need the equation to find the volume of a cone: where r=radius and h=height
Upon assessing this equation we also now know that we are missing a radius.
For a circle, the radius is the distance from the midpoint, center, to the border of the circle. The diameter is the distance from the border of one circle to another, passing through the midpoint. Knowing this, we can conclude that the diameter is two times the radius.
Using this information we can figure out the radius for this cone: 9 units.
Now that we have the radius, we can plug in the rest of the numbers with the correct placements.
square the 9 by calculating 9 times 9.
combine like terms and keep pi separate.
V=216 cubic units
Since this problem is asking for volume, we will used cubic units.
