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Liono4ka [1.6K]
3 years ago
11

The circumference of a circle is 25π cm. What is the area, in square centimeters? Express your answer in terms of \piπ.

Mathematics
2 answers:
creativ13 [48]3 years ago
5 0

Answer:

A = 156.25 pi  cm^2

Step-by-step explanation:

The circumference of a circle is given by

C = 2 * pi *r

25 pi = 2 * pi *r

Divide each side by 2 pi

25 pi/2 pi  = 2 pi r / 2 pi

12.5 = r

We can find the area by

A = pi r^2

A = pi ( 12.5) ^2

A = 156.25 pi  cm^2

marissa [1.9K]3 years ago
4 0
Other guy is correct
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ycow [4]

Answer:

  7)  (f+g)(x) = 4^x +5x -5

  8)  (f-g)(x) = 4^x +x +5

Step-by-step explanation:

7) add the two expressions.

  (f+g)(x) = f(x) +g(x) = (4^x +3x) +(2x -5)

  (f+g)(x) = 4^x +5x -5

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8) subtract g(x) from f(x).

  (f-g)(x) = f(x) -g(x) = (4^x +3x) -(2x -5) = 4^x +3x -2x +5

  (f-g)(x) = 4^x +x +5

7 0
3 years ago
Distribute. -3(-2x - 1)
ANTONII [103]

I believe the answer should be 6x+3

6 0
3 years ago
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What are the first five multiples of 12? Type the multiples in increasing order.
Mashutka [201]

Answer:12, 24, 36, 48, 60

6 0
3 years ago
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Which answer is the best explanation for how to check to see that the difference has been calculated correctly for this problem?
scoundrel [369]
A. No, because if you add 76.5 and 4.32, you'll get 80.82 instead of 72.18.

B. Yes, because if you add 72.18 and 4.32 you'll get 76.5

C. No, because if you substract 4.32 from 72.18, you'll get 67.86 instead of 76.5.

D. No, because if you add 76.5 and 72.18, you'll get 144.65 instead of 4.32.

Correct answer: B
4 0
3 years ago
What is the answer to these question?
Natali5045456 [20]

Answer:

2.  y = 7/2 x -2

3.   y = 3/4x-1

Step-by-step explanation:

points (0,-2)  (4,12)

slope = (y2-y1)/(x2-x1)

slope = (12--2)/(4-0)

    = (12+2)/4

   = 14/4 = 7/2

the slope is 7/2 and the y intercept is -2

y = mx+b

y = 7/2 x -2


points (0,-1)  (4,2)

slope = (y2-y1)/(x2-x1)

slope = (2--1)/(4-0)

    = (2+1)/4

   = 3/4

the slope is 3/4 and the y intercept is -1

y = mx+b

y = 3/4x-1

3 0
3 years ago
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