Answer:
part 1) 0.78 seconds
part 2) 1.74 seconds
Step-by-step explanation:
step 1
At about what time did the ball reach the maximum?
Let
h ----> the height of a ball in feet
t ---> the time in seconds
we have

This is a vertical parabola open downward (the leading coefficient is negative)
The vertex represent a maximum
so
The x-coordinate of the vertex represent the time when the ball reach the maximum
Find the vertex
Convert the equation in vertex form
Factor -16

Complete the square


Rewrite as perfect squares

The vertex is the point 
therefore
The time when the ball reach the maximum is 25/32 sec or 0.78 sec
step 2
At about what time did the ball reach the minimum?
we know that
The ball reach the minimum when the the ball reach the ground (h=0)
For h=0



square root both sides


the positive value is

Combine Like Terms:
=4xy+6+−x+−24
=(4xy)+(−x)+(6+−24)
=4xy+−x+−18
Answer:
=4xy−x−18
Y=-2x+0 haahahaha hope i helped i think
Answer:
71°
Step-by-step explanation:
The triangle shown is an isosceles triangle. Isosceles triangles have two equal sides and two equal angles. When all 3 angles are added, it should have a sum of 180°. The tip of the triangle is the part of the triangle with the smallest degree/angle. So the two remaining angles are the same amount.
180°=38°+x+?
180°=38°+71°+71°
Both missing angles are the same degree, and when both are added to 38, it has a sum of 180. x is equal to 71°.