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Elanso [62]
2 years ago
5

Need help with these math questions

Mathematics
1 answer:
PSYCHO15rus [73]2 years ago
4 0

\sqrt{16-x}        x = 8

Since x = 8, you can plug in/substitute 8 for "x" in the equation:

\sqrt{16-x}

\sqrt{16-8}

\sqrt{8}

2.82842

2.83 You answer is the 4th option


\sqrt{x+7}     x = 9

Plug in 9 for "x" in the equation

\sqrt{x+7}

\sqrt{9+7}

\sqrt{16}

4    Your answer is the 1st option

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9

Step-by-step explanation:

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Read 2 more answers
Can someone please help me??
olga2289 [7]
You would have to multiply then subtract
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2 years ago
What's the next step to substitution for this equation -4+y=-4
Marina86 [1]
Subtract the y then add the 4 to the other side so y=0
6 0
3 years ago
A rectangular solid with a square base has a volume of 4096 cubic inches - determine the dimensions that yield the minimum surfa
Bumek [7]

Answer:

side of base, a = 10.1 inches, height, h = 40.1 inches

Step-by-step explanation:

Volume of rectangular solid, V = 4096 cubic inches

Let the side of base is a and the height is h.

V = a^2h\\\\4096 = a^2 h ..... (1)

surface area of the solid  

S = 2a^2 + 4 ah \\\\S = 2a^2 + 4 \times a \times \frac{4096}{a^2}    from (1)\\\S = 2a^2 + \frac{4096}{a}\\\\\frac{dS}{da}= 4 a - \frac{4096}{a^2}\\\\4 a - \frac{4096}{a^2} = 0 \\\\a^3 = 1024\\\\a =10.1 inches

So, h = 40.2 inches

5 0
2 years ago
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