Need help with these math questions

10(a-2.5+0.56b) is this equivalent to 10a - 25+56b

kirill115 [55]

Hey there!

10(a - 2.5 + 0.56b)

= 10(a) + 10(-2.5) + 10(0.56b)

= 10a - 25 + 5.6b

= 10a + 5.6b - 25

Therefore, your answer is: 10a + 5.6b - 25

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

3 0

2 years ago

Rationalise the denominator.<br>1/√5+√2

Pani-rosa [81]

Answer:

Exact Form:

√5 + 5√2

__________

5

Decimal Form:

1.86142715

…

Step-by-step explanation:

N/A

3 0

2 years ago

Read 2 more answers

-5/6x = -10/3<br> solve for x

ololo11 [35]

Answer:

x = 4

Step-by-step explanation:

First you need to multiply both sides of the equation by -6/5

-6/5 × (-5/6x) = -6/5 × -10/3

Then you need to calculate and reduce. First, you'll reduce the numbers with the greatest common divisor, 6.

1/5 × 5x = -6/5 × (-10/3)

then reduce the greatest common divisor, 5

x = -6/5 × (-10/3)

Then multiply (multiplying two negatives equals a positive)

x = 6/5 × 10/3

reduce the greatest common divisor, 3

x = 2/5 × 10

reduce the greatest common divisor, 6

x = 2 × 2

x = 4

(i know this is confusing, sorry)

8 0

3 years ago

Please help!

Gemiola [76]

The earning of the salesperson is an illustration of a linear function.

The possible functions in the two scenarios are: $\mathbf{I(s) = 0.1s + 2500}$ and $\mathbf{I(s) = 0.05s + 2000}\\$

The function is given as:

$\mathbf{I(s) = 0.1s + 2000}$

When the base salary is increased, a possible function is:

$\mathbf{I(s) = 0.1s + 2500}$

This is so, because 2500 is greater than 2000

When the commission rate is decreased, a possible function is:

$\mathbf{I(s) = 0.05s + 2000}\\$

This is so, because 0.05 is less than 0.1

So, the possible functions in the two scenarios are:

$\mathbf{I(s) = 0.1s + 2500}$ and $\mathbf{I(s) = 0.05s + 2000}\\$

See attachment for the graphs of both functions

Read more about linear equations at:

brainly.com/question/21981879

5 0

2 years ago

A dairy farm uses the somatic cell count (SCC) report on the milk it provides to a processor as one way to monitor the health of

Eva8 [605]

Answer:

$t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37$

$p_v =P(t_{4}>2.37)=0.038$

If we compare the p value and a significance level assumed $\alpha=0.1$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.

Step-by-step explanation:

Data given and notation

$\bar X=250000$ represent the sample mean

$s=37500$ represent the standard deviation for the sample

$n=5$ sample size

$\mu_o =210250$ represent the value that we want to test

$\alpha=0.1$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the mean is higher than 210250, the system of hypothesis would be:

Null hypothesis: $\mu \leq 210250$

Alternative hypothesis: $\mu > 210250$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37$

Now we need to find the degrees of freedom for the t distirbution given by:

$df=n-1=5-1=4$

Conclusion

Since is a one right tailed test the p value would be:

$p_v =P(t_{4}>2.37)=0.038$

If we compare the p value and a significance level assumed $\alpha=0.1$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.

6 0

3 years ago