2 years ago

Need help with these math questions

Mathematics

1 answer:

PSYCHO15rus [73]2 years ago

4 0

$\sqrt{16-x}$ x = 8

Since x = 8, you can plug in/substitute 8 for "x" in the equation:

$\sqrt{16-x}$

$\sqrt{16-8}$

$\sqrt{8}$

2.82842

2.83 You answer is the 4th option

$\sqrt{x+7}$ x = 9

Plug in 9 for "x" in the equation

$\sqrt{x+7}$

$\sqrt{9+7}$

$\sqrt{16}$

4 Your answer is the 1st option

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