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Elanso [62]
3 years ago
5

Need help with these math questions

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
4 0

\sqrt{16-x}        x = 8

Since x = 8, you can plug in/substitute 8 for "x" in the equation:

\sqrt{16-x}

\sqrt{16-8}

\sqrt{8}

2.82842

2.83 You answer is the 4th option


\sqrt{x+7}     x = 9

Plug in 9 for "x" in the equation

\sqrt{x+7}

\sqrt{9+7}

\sqrt{16}

4    Your answer is the 1st option

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