All categories

3 years ago

NEED HELP PLEASE!!!! (10 PTS)

1 answer:

5 0

Tigers:-

f(t) = 7(1 + 0.1)^2 where t = number of years

Eagle

g(t) = 15 + 2t

B after ten year number tigers = f(t) = 7(1 + 0.1)^10 = 18

number of eagles = 15 + 10(2) = 35

C when the number of tigers = number eagles the 2 functions will be equal;-

f(t) = g(t) that is:-

7* 1.1^t = 15 + 2t

solve for t

You might be interested in

Convert. 2/3and 4/6 into like fraction

Luden [163]

Answer:

Answer given below

Step-by-step explanation:

When we calculate the LCM, you get it as 6.

So both the fractions should have a denominator 6.

For that, in 2/3 we should multiply both numerator and denominator with 2 so that denominator becomes 6.

When we convert to like fraction, 2/3 becomes 4/6.

Now both the fractions have common denominator

Hope it helps.

5 0

3 years ago

Read 2 more answers

A food company sells salmon to various customers. The mean weight of the salmon is 37 lb with a standard deviation of 2 lbs. The

brilliants [131]

Answer:

The standard deviation for the mean weigth of Salmon is 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount order stores.

Step-by-step explanation:

The mean sample of the sum of n random variables is

$\overline{X} = \frac{X_1+X_2+...+X_n}{n}$

If $X_1, ..., X_n$ are indentically distributed and independent, like in the situation of the problem, then the variance of $X_1 + .... + X_n$ will be the sum of the variances, in other words, it will be n times the variance of $X_1$ .

However if we multiply this mean by 1/n (in other words, divide by n), then we have to divide the variance by 1/n², thus $\overkine{X} = \frac{V(X_1)}{n}$ and as a result, the standard deviation of $\overline{X}$ is the standard deviation of $X_1$ divided by $\sqrt{n}$ .

Since the standard deviation of the weigth of a Salmon is 2 lbs, then the standard deviations for the mean weigth will be:

Restaurants: We have boxes with 9 salmon each, so it will be $\frac{2}{\sqrt{9}} = \frac{2}{3}$
Grocery stores: Each carton has 49 salmon, thus the standard deviation is $\frac{2}{\sqrt{49}} = \frac{2}{7}$
Discount outlet stores: Each pallet has 64 salmon, as a result, the standard deviation is $\frac{2}{\sqrt{64}} = \frac{1}{4}$

We conclude that de standard deivation of the mean weigth of salmon of the types of shipment given is: 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount outlet stores.

7 0

3 years ago

** PLEASE HELP!!! HURRY!!! 30 POINTS AND BRAINLIEST FOR QUICKEST CORRECT ANSWER!!!!!!!*****

zzz [600]

This is Hard but I tried Hope this Helps.
22-2+20 = 0x=12.2 |y
|
|
__________|__________x_
|
20.5 |
2 10 |
1 |
m=Months 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

7 0

4 years ago

Common denominator of 6/7 and 7/13

ira [324]

For the denominators (7, 13) the least common multiple (LCM) is 91.

Therefore, the least common denominator (LCD) is 91.

Rewriting the original inputs as equivalent fractions with the LCD:
78/91, 49/91.

4 0

4 years ago

The Canadian labor force as of 2019 was 32.7 million. There were 30.9 million employed What the unemployment rate would be?

Afina-wow [57]

Answer:

The unemployment rate would be 5.5%.

Step-by-step explanation:

It is given that,

The Canadian labor force as of 2019 was 32.7 million.

There were 30.9 million employed

We need to find the unemployment rate.

Unemployed = labor force - employed

= 32.7 - 30.9

= 1.8 million

$\text{unemployment rate}=\dfrac{\text{unemployed}}{\text{labor force}}\times 100\\\\=\dfrac{1.8}{32.7}\times 100\\\\=5.5\%$

So, the unemployment rate would be 5.5%.

8 0

3 years ago