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adelina 88 [10]
3 years ago
6

The front row in a movie theater has 23 seats. If you were asked to sit in the seat that occupied the median position, in which

seat would you have to sit?
Mathematics
1 answer:
Scorpion4ik [409]3 years ago
3 0

Answer:

You would have to sit in the 12th seat. (12)

Step-by-step explanation:

The median is the middle number in a sorted, ascending or descending, list of numbers.

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Solve this formula for the velocity for (d)<br><br> Show your work
Vinvika [58]

Answer:

d = vt

Step-by-step explanation:

Step 1: Write equation

v = d/t

Step 2: Multiply both sides by t

vt = d

Step 3: Rewrite

d = vt

7 0
3 years ago
A plumber charges a flat fee of $76 to visit a home and examine a clogged drain. The plumber charges an additional $24 per hour
prisoha [69]

Answer:

(a) 12 hours

(b) $220

Step-by-step explanation:

(a) First we plug in $364 for C

C=76+24h

364=76+24h

Subtract 76 from both sides

24h=288

Divide both sides by 24

h=12

She spent 12 hours fixing the drain

(b) First we plug 6 hours in for h

C=76+24(6)

Multiply it out

C=76+144

Add

C=220

It costs $220 for fixing a drain that takes 6 hours

5 0
2 years ago
Deshi has 427 marbles and Elaheh has 394 marbles Deshi wants to give 125 marbles to his little brother how many total marbles wi
hjlf

Answer: Deshi will have 302 marbles  and Elaheh will have 519.

Step-by-step explanation:

Deshi's Marbles will subtract 125.

427 - 125 = 302.

Elaheh's Marbles will add 125.

394 + 125= 519.

3 0
2 years ago
The question is in the picture <br> PLEASE HURRY!!!!
dsp73

Answer:

1, 3, 5

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What is the probability of drawing a 3 or a 4 or a heart from a deck of cards?
Effectus [21]
\Omega=\{2\spadesuit;\ 3\spadesuit;...;A\spadesuit;2\heartsuit ;\ 3\heartsuit;...;A\heartsuit;\ 2\diamondsuit;\ 3\diamondsuit;...;A\diamondsuit;\ 2\clubsuit;\ 3\clubsuit;...;A\clubsuit\}\\\\|\Omega|=52\\\\A=\{3\spadesuit;\ 4\spadesuit;\ 3\diamondsuit;\ 4\diamondsuit;\ 3\clubsuit;\ 4\clubsuit;\ 2\heartsuit;\ 3\heartsuit;\ 4\heartsuit;...;A\heartsuit\}\\\\|A|=2+2+2+13=19\\\\P(A)=\dfrac{|A|}{|\Omega|}\to P(A)=\dfrac{19}{52}

Answer:\ \dfrac{19}{52}
5 0
3 years ago
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