Ask question

Ask question

All categories

adelina 88 [10]

3 years ago

6

The front row in a movie theater has 23 seats. If you were asked to sit in the seat that occupied the median position, in which

seat would you have to sit?

1 answer:

Scorpion4ik [409]3 years ago

3 0

Answer:

You would have to sit in the 12th seat. (12)

Step-by-step explanation:

The median is the middle number in a sorted, ascending or descending, list of numbers.

You might be interested in

pascal wanted the area of the door to be 54 square feet and the width still to be 2/3 the length. what would the dimensions of t

dlinn [17]

The floor wood be 81 dimensions.

8 0

3 years ago

Read 2 more answers

express rental car charges $40 rental fee, $15 for gas and $.25 mile driven. for the same car, reynolds rental car charges $45 f

alexgriva [62]

Here you go! Sorry for the bad handwriting :/

3 0

3 years ago

Find the vector projection of B onto A if A = 5i + 11j – 2k,B = 4i + 7k

valkas [14]

Answer:

$\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\$

Step-by-step explanation:

Given A = 5i + 11j – 2k and B = 4i + 7k, the vector projection of B unto a is expressed as $proj_ab = \dfrac{b.a}{||a||^2} * a$

b.a = (5i + 11j – 2k)*( 4i + 0j + 7k)

note that i.i = j.j = k.k =1

b.a = 5(4)+11(0)-2(7)

b.a = 20-14

b.a = 6

||a|| = √5²+11²+(-2)²

||a|| = √25+121+4

||a|| = √130

square both sides

||a||² = (√130)

||a||² = 130

$proj_ab = \dfrac{6}{130} * (5i+11j-2k)\\\\proj_ab = \frac{30}{130} i+\frac{11}{130} j-\frac{12}{130} k\\\\proj_ab = \frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\\\$

<em>Hence the projection of b unto a is expressed as </em> $\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\$ <em></em>

7 0

3 years ago

ANSWER PLZ QUICK AND FAST

stich3 [128]

Subtract 9 from both sides

7 0

4 years ago

Read 2 more answers

Can someone help me please?

Alik [6]

Answer:

C.

Step-by-step explanation:

The reds are counting up in whole numbers by one integer.

Hope this helps!

If not, I am sorry.

5 0

2 years ago