1. How much interest would you pay on a loan of $1,230 for 15 months at 15 percent APR if the interest is 18.75 per $100?
The chart probably refers to interest per $100 of loan. So, the interest for a $1,230 loan would be (1230/100) * 18.75 = 230.625 ~ 230.63
So, the answer will be B $230.63.
2. Sherri borrowed $3,200 at 13 percent APR for 18 months. If she must pay 19.5 per $100, what is the total interest?
3,200 / 100 = 32 ... x 19.5 = 624
Principal x int rate x time = 3200 x .13 x 1.5 yr = 624 interest
So, the answer will be the A $624.
3. What is the total amount that Sherri (in question number 2) will repay?
The correct answer will be the $3,824.
Explanation:
The Journal Entry from July 1 and July 31 is shown below:-
1. Cash Dr, $560
To Deferred revenue $560
(Being cash is received)
2. Deferred revenue $336
To Sales revenue $336
(Being 12 months sales service is recorded)
3. Cost of goods sold $280
To Inventory $280
(Being cost of goods sold is recorded)
4. Deferred revenue ($336 ÷ 12) $28
To Service revenue $28
(Being Deferred service revenue is recorded)
Working Note:-
Cellular service revenue = offer price ÷ total cost of phone and service × cellular service
= (($560 ÷ ($448 + $672)) × $672
= $336
Answer:
$33,840
Explanation:
The computation of the depreciation per units or tons under the units-of-production method is shown below:
= (Original cost - residual value) ÷ (estimated tons)
= ($158,400 - $0) ÷ (22,000 tons)
= ($158,400) ÷ (22,000 tons)
= $7.20 per tons
Now for the year 2021, it would be
= Tons during 2021 × depreciation per tons
= 4,700 × $7.20 per tons
= $33,840
Answer:
The optimal usage of fabric = 2
Explanation:
Given the quantity, Q = 10 + 4F - (1/3) F^3
Selling price = $20
Profit = TR - TC
There is no variable cost and let the fixed cost is constant G.
Profit = PQ - G
Profit = 20(10 + 4F − (1/3)F^3)) - G = 0
Now take the first order derivative:
d(profit) / dF = 0
20(4 - F^2) = 0
F = 2
Therefore the optimal usage of fabric = 2
1,3,4,6
i think, good luck!