Answer:
The other angles of the isosceles triangle are 65° and 50°
Step-by-step explanation:
By definition, the base angles of an isosceles triangle are equal, therefore, we have;
Where one of the base angles = 65°, the other base angle = 65°
To find the third angle, we proceed as follows
Let the third angle = ∠3
Let the two base angles = ∠1, and ∠2 such that ∠1 = ∠2 = 65°
Where ∠1 = 65° is the known base angle
By the sum of the interior angles of a triangle theorem, we have;
∠3 + ∠1 + ∠2 = 180°
∴ ∠3 + 65 ° + 65° = 180°
∠3 = 180° - (65 ° + 65°) = 180° - 130° = 50° By angle subtraction postulate
∴ The third angle = ∠3 = 50°
The other angles of the isosceles triangle are ∠2 = 65° and ∠3 = 50°.
You are correct stuck with that
For this case we have the following expression:
root (q / 36)
We can rewrite the expression.
We have then:
root (q) / root (36)
Then, calculating the square root in the denominator we have:
root (q) / 6
Answer:
root (q) / 6
option A
8/10 + 2/100 = 80/100 + 2/100 = 82/100.
Hope this helps !
Photon
Answer:
A=68
Step-by-step explanation:
