Slope intercept form is y=mx+b where m is the slope and b is the y intercept. we have the slope is -6 and a point so the beat way to solve is to use point slope form and si.plify this into y intercept forn.
point slope is (y-y1)=m(x-x1) where (x1,y1) is a point o. the line. so we get
(y-8)=-6(x-(-2))
y-8=-6(x+2)
y-8=-6x-12
y=-6x-4
now we have slope intercept form!
The discriminant is 164 and there are two real solutions.
What is Quadratic equation?
A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax^2 + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term.
We can find the discriminant as shown below:
x^2+14x+8=0
a=1, b=14, c=8
Discriminant=b^2-4ac
=(14)^2-4*1*8
=196-32
=164>0
As the discriminant is positive and greater than zero. So, there are two real and distinct solution.
Hence, discriminant is 164 and two real solution.
Learn more about Quadratic equation here:
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Length = area / width
= 264 / 11
= 24 yards
Your answer is 134! Hope this helps!