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Finger [1]
3 years ago
5

Find the total area of 2cm 8cm 9cm 1cm 7cm 7cm

Mathematics
1 answer:
Yuki888 [10]3 years ago
6 0
The total area would be 7056 i believe
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Help me graph it please
VikaD [51]
Here's a rough graph haha
the graph has a factor of 4/1 (considered the "slope"), and the vertex is translated 2 units to the right (whatever is in the | lines | has the negative/positive flipped), and 6 units down.

8 0
3 years ago
Is it possible to prove DOG is con to GED?​
blagie [28]

Answer:

Yes

Step-by-step explanation:

The angles are identical, so they are congruent.

Hope I helped! Plz leave a comment and a rating!

8 0
3 years ago
Help With IXL P.10 plz!!!<br> Write you snap/insta down below, if you know how to do this please!!
Misha Larkins [42]

Answer:

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Step-by-step explanation:

8 0
2 years ago
–5(3 – q) + 4 = 5q – 11
mrs_skeptik [129]

Answer:

0

Step-by-step explanation:

–5(3 – q) + 4 = 5q – 11

-15 +5q + 4 = 5q -11

-11 + 5q = 5q - 11

+5q - 5q = -11 + 11

0=0

6 0
3 years ago
What line is parallel to 2x+5y=6 that goes through (5,3)
Anna11 [10]

Answer:

4y = x - 17

Step-by-step explanation:

First off, in the equation given : 2x + 5y = 6 , make y the subject of the formula which will give y = \frac{-2x}{5} + \frac{6}{5}  which make the gradient, m, the coefficient of x = \frac{-2}{5}  . Since the line we're looking for is parallel to the one we were given, their respective gradients would be the same. (If they were perpendicular, the gradient of the new line would be a negative inverse of the given line)

Then you proceed to use the one-point formula : y - y₀ = m(x - x₀), where   y₀ = 3 and x₀ = 5 from the point it goes through (5, 3)

y - 3 = \frac{1}{4}(x - 5); y - 3 = \frac{x}{4} - \frac{5}{4};  y = \frac{x}{4} - \frac{5}{4} +3

y = \frac{x}{4} - \frac{17}{4};  y = \frac{x-17}{4}  ;   4y = x - 17

7 0
2 years ago
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