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Airida [17]
3 years ago
13

A. 205.7 m^3

Mathematics
1 answer:
Gemiola [76]3 years ago
8 0

Answer:  221.4 m³  If you are just looking for the volume of the triangular prism.

Step-by-step explanation:  Volume of the prism is the Area of the base times the height.

The Area of the triangular base = width × height ÷ 2

Width = 12m   height =  4.1m = 49.2m Divided by 2 =

24.6m² is the Area of the base

The height of the base is 9m

24.6 × 9 = 221.4 cubic meters

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A bag contains yellow marbles and red marbles, 23 in total. The number of yellow marbles is 4 less than 2 times the number of re
Orlov [11]
First let’s express the total number of marbles as such:
y(yellow marbles) + r(red marbles)=23; y+r=23

now let’s express the relation of yellow marbles to red marbles:
y=2r(2 times red marbles) - 4(4 less marbles); y=2r-4

since we figured out what y equals, we can plug into the first equation we created:
(2r-4)+r=23

now solve for r:
2r-4+r=23
combine like terms
3r-4=23
add 4 to both sides
3r=27
divide both side by 3
r=9

plug r back into first equation and solve for y:
y+9=23
subtract 9
y=14

there are 9 red marbles and 14 yellow marbles!


3 0
3 years ago
manuel deposits $10000 for 12 yr in an account paying 4% compounded annually.He then puts this total amount on deposit in anothe
Naddik [55]
\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$10000\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &12
\end{cases}
\\\\\\
A=10000\left(1+\frac{0.04}{1}\right)^{1\cdot 12}\implies A=1000(1.04)^{12}\\\\\\ A\approx 16010.32

he then turns around and grabs that money and sticks it for another 9 years,

\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
~~
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$16010.32\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2\\
t=years\to &9
\end{cases}
\\\\\\
A=16010.32\left(1+\frac{0.05}{2}\right)^{2\cdot 9}\implies A=16010.32(1.025)^{18}
\\\\\\
A\approx 24970.64

add both amounts, and that's how much is for the whole 21 years.
6 0
4 years ago
Help please this is due in a couple minutes!!!! Anyone know the answer??!!!?
givi [52]

Answer:

the second one

Step-by-step explanation:

correct me if it is wrong

7 0
3 years ago
Rachel finished 3 over 4 of the race in 6 hours. How long was the entire race?
MrRissso [65]

Answer:

8 hours long

Step-by-step explanation:

3/4 of the race in 6 hrs  

6 divided by 3 equals 2  

so 1/4 is 2 hrs, 2/4 is 4 hrs, 3/4 is 6 hrs which means 4/4 the whole race would be 8 hrs  

4 multiplied by 2 would give you 8  

so the entire race was (8 hours long)

4 0
3 years ago
Read 2 more answers
A dairy needs 325 gallons of milk containing 5% butterfat. How many gallons each of milk containing 6% butterfat and milk contai
zubka84 [21]

The amount of milk containing 6% butterfat and 1% butterfat are 260 gallons and 65 gallons respectively.

<u><em>Explanation</em></u>

Suppose, the amount of milk containing 6% butterfat is x gallons

As the amount of mixture of milk should be 325 gallons, so the amount of milk containing 1% butterfat will be: (325-x) gallons

Given that, the mixture of milk is containing 5% butterfat. So, the equation will be....

0.06x+0.01(325-x)=0.05*325\\ \\ 0.06x+3.25-0.01x=16.25\\ \\ 0.05x= 13\\ \\ x= \frac{13}{0.05}=260

So, the amount of milk containing 6% butterfat is 260 gallons and the amount of milk containing 1% butterfat is (325-260) gallons = 65 gallons.

8 0
3 years ago
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