Answer:
Step-by-step explanation:
lateral surface area=(sum of sides)×height
Total surface area =2×base area +lateral area
The measure of the angle ∠PQR is 90 degrees
<h3>How to prove that ∠PQR is 90 degrees?</h3>
The equation of the line PQ is given as:
3x - y - 2 = 0
The coordinates of the QR are given as:
(0, -2) and (6, -4)
Make y the subject in 3x - y - 2 = 0
y = 3x - 2
The slope of the above line is
m1 = 3
Next, we calculate the slope (m2) of points Q and R.
So, we have:
m2 = (y2- y1)/(x2 - x1)
This gives
m2 = (-4 + 2)/(6 - 0)
Evaluate
m2 = -1/3
The slopes of perpendicular lines are opposite reciprocals.
m1 = 3 and m2 = -1/3 are opposite reciprocals.
This means the lines PQ and QR are perpendicular lines.
The angle at the point of perpendicularity is 90 degrees
Hence, the measure of the angle ∠PQR is 90 degrees
Read more about linear equations at:
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10:4
35:14
55:22
10:4 divided by 2:2=5:2
35:14 divided by 7:7= 5:2
55:22 divided by 11:11= 5:2
Answer:
2
Step-by-step explanation:
Use the intercept method. Where is y when x = 0?
To find the slope of the line, first find the slope of 3x + y = 5, and then its opposite reciprocal.
3x + y = 5
y = -3x + 5
the slope of 3x + y = 5 is -3.
the slope is -3, so the opposite reciprocal slope is 1/3.
the equation of any line is y = ax + b
to find this line, y = 3, x = -9, and the slope is 1/3.
3 = -9a + b
3 = -9 (1/3) + b
3 = -3 +b
b = 6
substitute a and b into the equation
y = ax + b
y = 1/3x + 6
the equation of the line is y = 1/3x + 6.
