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3 years ago

What is the solution to the equation + 5= 8?

Mathematics

2 answers:

evablogger [386]3 years ago

8 0

Answer: 3 + 5 = 8

Step-by-step explanation: if you subtract 5 from 8 (8-5=3) you get 3 so that is your answer

egoroff_w [7]3 years ago

7 0

Answer:

x=13x=13

Step-by-step explanation:

x−5=8

Add 55 to both sides.

x=8+5x=8+5

Simplify 8+58+5 to 1313.

x=13x=13

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Find the volume of the wedge-shaped region (Figure 1) contained in the cylinder x2+y2=81 and bounded above by the plane z=x and

Natali5045456 [20]

In cylindrical coordinates, the volume is given with

$\displaystyle\int_{\theta=-\pi/2}^{\theta=\pi/2}\int_{r=0}^{r=9}\int_{z=0}^{z=r\cos\theta}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle\int_{\theta=-\pi/2}^{\theta=\pi/2}\int_{r=0}^{r=9}r^2\cos\theta\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle\left(\int_{\theta=-\pi/2}^{\theta=\pi/2}\cos\theta\,\mathrm d\theta\right)\left(\int_{r=0}^{r=9}r^2\,\mathrm dr\right)$
$=486$

7 0

3 years ago

Read 2 more answers

Solve the equation and find the value of the variable

djyliett [7]

The sum of the angles should be 180, so x+ (x+10) + (x+5) = 180. This simplifies to 3x + 15 = 180, so 3x = 165, so x=55.

3 0

3 years ago

A perfume company claims that the mean weight of ther new perfume is at least 8.9 fluid oz. Express the null hypothesis and the

zlopas [31]

Answer:

$H0: mu = 8.9 fl oz.\\\\$

$Ha: mu ≠8.9 fluid oz$

Step-by-step explanation:

Given that A perfume company claims that the mean weight of ther new perfume is at least 8.9 fluid oz

For testing this claim, in Statistics we perform a certain measures called hypothesis testing.

For this first step is to create null and alternate hypothesis.

Normally null hypothesis would have some statistic = something

Here we want to test the mean weight of perfume

Hence null hypothesis would be

H0: mu = 8.9 fl oz.

Alternate hypothesis would be opposite of this claim

i.e.

Ha: mu ≠8.9 fluid oz

Hence answer is

$H0: mu = 8.9 fl oz.\\\\$

$Ha: mu ≠8.9 fluid oz$

6 0

3 years ago

Evaluate BC for A = 5, B = 4, and C = 2.<br> 06

VARVARA [1.3K]

Answer:Its 8.24

Step-by-step explanation:

4 times 2.06 is 8.24 :}

3 0

3 years ago

Read 2 more answers

NO LINKS!!! Part 2: Find the Lateral Area, Total Surface Area, and Volume. Round your answer to two decimal places.

slava [35]

Answer:

<h3><u>Question 7</u></h3>

<u>Lateral Surface Area</u>

The bases of a triangular prism are the triangles.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the triangles (bases).

$\implies \sf L.A.=2(10 \times 6)+(3 \times 6)=138\:\:m^2$

<u>Total Surface Area</u>

Area of the isosceles triangle:

$\implies \sf A=\dfrac{1}{2}\times base \times height=\dfrac{1}{2}\cdot3 \cdot \sqrt{10^2-1.5^2}=\dfrac{3\sqrt{391}}{4}\:m^2$

Total surface area:

$\implies \sf T.A.=2\:bases+L.A.=2\left(\dfrac{3\sqrt{391}}{4}\right)+138=167.66\:\:m^2\:(2\:d.p.)$

<u>Volume</u>

$\sf \implies Vol.=area\:of\:base \times height=\left(\dfrac{3\sqrt{391}}{4}\right) \times 6=88.98\:\:m^3\:(2\:d.p.)$

<h3><u>Question 8</u></h3>

<u>Lateral Surface Area</u>

The bases of a hexagonal prism are the pentagons.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the pentagons (bases).

$\implies \sf L.A.=5(5 \times 6)=150\:\:cm^2$

<u>Total Surface Area</u>

Area of a pentagon:

$\sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}a^2$

where a is the side length.

Therefore:

$\implies \sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}\cdot 5^2=43.01\:\:cm^2\:(2\:d.p.)$

Total surface area:

$\sf \implies T.A.=2\:bases+L.A.=2(43.01)+150=236.02\:\:cm^2\:(2\:d.p.)$

<u>Volume</u>

$\sf \implies Vol.=area\:of\:base \times height=43.011193... \times 6=258.07\:\:cm^3\:(2\:d.p.)$

8 0

2 years ago