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3 years ago

How do the alkali metals differ from the alkaline earth metals?

Chemistry

1 answer:

Alik [6]3 years ago

7 0

Answer & Explanation:

The alkali metals are the elements found in the first group of the periodic table.

Alkaline earth metals are found in the second group of the periodic table.

Alkali metals are Lithium (Li), sodium(Na), potassium (K), Rubidium (Rb), Cesium (Cs) and Francium (Fr).

Alkaline earth metals include; Beryllium (Be), Magnesium (Mg), Calcium (Ca), Strontium (Sr), Barium (Ba) and Radium (Ra).

Alkali metals are very reactive and none of these metals do not occur as free metals in nature.
Alkaline metals are also do not occur freely in nature and they are also very reactive.

For alkali elements, the densities of Lithium and Sodium are less than the density of water. However, the other elements are denser than water. Many of alkali metal compounds (NaCl, KCl, Na2, CO3, NaOH) are commercially very important.

Alkaline elements in this group are denser than water.

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What are homogenous mixtures

svetoff [14.1K]

Answer:

a mixture in which the composition is uniform throughout the mixture.

Explanation:

7 0

3 years ago

Read 2 more answers

What is the concentration of magnesium bromide, in ppm, if 133.4 g MgBr2 dissolved in 1.84 L water. Then solve for the bromine c

Serhud [2]

Answer: 0.0725ppm

Explanation:

133.4g of MgBr2 dissolves in 1.84L of water.

Therefore Xg of MgBr2 will dissolve in 1L of water. i.e

Xg of MgBr2 = 133.4/1.84 = 72.5g

The concentration of MgBr2 is 72.5g/L = 0.0725mg/L

Recall,

1mg/L = 1ppm

Therefore, 0.0725mg/L = 0.0725ppm

7 0

3 years ago

Calculate the density in g/l of co2 gas at 27 Celsius and 0.500 atm pressure

lesya692 [45]

Answer:

The density of CO₂ gas at 27 Celsius and 0.500 atm is 0.89 $\frac{grams}{L}$

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P*V = n*R*T Equation (A)

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

Density allows you to measure the amount of mass in a given volume of a substance. So density is defined as the quotient between the mass of a body and the volume it occupies:

$density=\frac{mass}{volume}$

Being the molar mass of a substance the mass contained in one mole of said substance, the number of moles can be expressed as:

$n=\frac{mass}{molar mass}$ Equation (B)

Replacing in Equation (A):

P*V= $\frac{mass}{molar mass}$ *R*T

Solving to get the definition of density expressed in the equation, you get:

$density=\frac{mass}{V} =\frac{P*molar mass}{R*T}$

Being:

P=0.500 atm
Molar mass CO₂= 44 g/mole

R= 0.082 $\frac{atm*L}{mole*K}$

T= 27 C= 300 K (being 0 C=273 K)

and replacing:

$density=\frac{mass}{V} =\frac{0.500 atm*44 \frac{g}{mole} }{0.082 \frac{atm*L}{mole*K} *300 K}$

you get:

density= 0.89 $\frac{grams}{L}$

The density of CO₂ gas at 27 Celsius and 0.500 atm is 0.89 $\frac{grams}{L}$

3 0

4 years ago

In the background information, it was stated that CaF2 has solubility, at room temperature, of 0.00160 g per 100 g of water. How

____ [38]

Answer:

2.05*10⁻⁵ moles of CF₂ can dissolve in 100 g of water.

12.82 moles of CaF₂ will dissolve in exactly 1.00 L of solution

Explanation:

First, by definition of solubility, in 100 g of water there are 0.0016 g of CaF₂. So, to know how many moles are 0.0016 g, you must know the molar mass of the compound. For that you know:

Ca: 40 g/mole
F: 19 g/mole

So the molar mass of CaF₂ is:

CaF₂= 40 g/mole + 2*19 g/mole= 78 g/mole

Now you can apply the following rule of three: if there are 78 grams of CaF₂ in 1 mole, in 0.0016 grams of the compound how many moles are there?

$moles=\frac{0.0016 grams*1 mole}{78 grams}$

moles=2.05*10⁻⁵

2.05*10⁻⁵ moles of CF₂ can dissolve in 100 g of water.

Now, to answer the following question, you can apply the following rule of three: if by definition of density in 1 mL there is 1 g of CaF₂, in 1000 mL (where 1L = 1000mL) how much mass of the compound is there?

$mass of CaF_{2}=\frac{1000 mL*1g}{1mL}$

mass of CaF₂= 1000 g

Now you can apply the following rule of three: if there are 78 grams of CaF₂ in 1 mole, in 1000 grams of the compound how many moles are there?

$moles=\frac{1000 grams*1 mole}{78 grams}$

moles=12.82

12.82 moles of CaF₂ will dissolve in exactly 1.00 L of solution

5 0

3 years ago

[06.01]The same amount of heat is removed from 2 kg of water and from 1 kg of water starting at the same temperature. What will

liq [111]

Answer: The 1 kg of water will reach the lowest temperature

Both of the objects is water so their specific heat should be same. The heat removed from the 2kg of water which is 2 times of mass than the 1kg water. Since the heat removed, both of their temperatures will drops. But 2kg water temperature drops will be half of 1kg water.

6 0

3 years ago