Answer:
no solutions
Step-by-step explanation:
y = -3x +10
3x +y = 5
Substitute the first equation into the second equation
Let every instance of y in the second equation be replaced with -3x+10
3x+ (-3x+10) = 5
Combine like terms
10 =5
This is never true so there are no solutions
(These are parallel lines with the same slope but different y intercepts)
Adding 1/9 to both sides, we get 2/3+y=8/9. Next, 2/3 can be multiplied by 3/3 to get 6/9 due to that 3*3=9 and using the identity property. We then subtract 6/9 from both sides to get y=2/9
Answer:
The answer is 1/3x-1
Step-by-step explanation:
Let's simplify step-by-step.
5/6x−7−(1/2x−6)
Distribute the Negative Sign:
=5/6x−7+−1(1/2x−6)
=5/6x+−7+−1(1/2x)+(−1)(−6)
=5/6x+−7+−1/2x+6
Combine Like Terms:
=5/6x+−7+−1/2x+6
=(5/6x+−1/2x)+(−7+6)
=1/3x+−1
Answer:
=1/3x−1
1/sin^2x-1/tan^2x=
1/sin^2x-1/ (sin^2x/cos^2x)<<sin tan= sin/cos>>
= 1/sin^2x- cos^2x / sin^2x
= (1- cos^2x) / sin^2x <<combining into a single fraction>>
sin^2 x / sin^2x <<since 1- cos^2 x sin^2 x
=1
this simplifies to 1.
Answer:
The width of the photo is
.
Step-by-step explanation:
From the given figure it is notices that the total width of the frame is

The photo is covered by a frame border and the width of the border is

To find the width of the photo we have to subtract the width of upper frame border and lower frame border from the total width of frame.
Width of the photo is




Therefore the width of the photo is
.